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vovikov84 [41]
3 years ago
15

Find the 2nd term in expansion of (4-2x)⁴ Show steps

Mathematics
2 answers:
makkiz [27]3 years ago
8 0

<h3><em><u>ANSWER</u></em><em><u>:</u></em></h3>

\bold{(4-2x)^{4}   } 

\bold{[(4-2x)^{2}]^{2}   } 

\bold{(4-2x)^{2}(4-2x)^{2}   }

goblinko [34]3 years ago
5 0

\huge\mathfrak\pink{Answer}

(4 - 2x) ²

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Ket [755]

Your answer would be D. or B. I think but i know it's not A.

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3 years ago
Order the following from LEAST to GREATEST 21% , 3/20 , 25.6% , 2.24 , 0.24
True [87]

Answer:

Step-by-step explanation:

3/20 21% 0.24 25.6% 2.24

7 0
3 years ago
In 1990, the cost of tuition at a large Midwestern university was $95 per credit hour. In 1999, tuition had risen to $221 per cr
notsponge [240]

Answer:

The cost of tuition as a function of x, the number of years since 1990, is C(x)= 14*(x-1990) + 95

Step-by-step explanation:

A linear function is a polynomial function of the first degree that has the following form:

y= m*x + b

where

  • m is the slope of the function
  • n is the ordinate (at the origin) of the function

So, in this case: C(x)= m*( x-1990) + b where x is the number of years since 1990.

Given the coordinates of two points, it is possible to determine the slope m of the line from them using the following formula:

m=\frac{y2 - y1}{x2 - x1}

In this case, you know that in 1990, the cost of tuition at a large Midwestern university was $95 per credit hour. And in 1999, tuition had risen to $221 per credit hour. So:

  • x1= 1990
  • y1= 95
  • x2= 1999
  • y2= 221

So the value of m is:

m=\frac{221 - 95}{1999 - 1990}

m=\frac{126}{9}

m= 14

So C(x)= 14*( x-1990) + b. In 1999, tuition had risen to $221 per credit hour. Replacing:

221= 14*(1999 - 1990) + b

221= 14*9 +b

221= 126 + b

221 - 126= b

95= b

Finally, <u><em>the cost of tuition as a function of x, the number of years since 1990, is C(x)= 14*(x-1990) + 95</em></u>

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3 years ago
What matrix multiplication is possible ?
gizmo_the_mogwai [7]

Answer:

Firstly, it is important to note that the multiplication of matrices is done in this way:

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Now, two matrices can be multiplied only if their dimensions are compatible, which means that the number of columns in the first matrix must be​​ equal to the number of rows in the second matrix.

In other words:

Two matrices A and B are said to be multiplies if the number of columns in A coincides with the number of rows in B.

In this context, the correct option is:

\left[\begin{array}{c}1&-1\end{array}\right] \left[\begin{array}{cc}0&4\end{array}\right]

Where A is:

\left[\begin{array}{c}1&-1\end{array}\right]

And B is:

\left[\begin{array}{cc}0&4\end{array}\right]

As you can see, the number of columns in A coincides with the number of rows in B

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