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2 years ago

15

Find the 2nd term in expansion of (4-2x)⁴ Show steps

2 answers:

makkiz [27]2 years ago

8 0

<h3><em><u>ANSWER</u></em><em><u>:</u></em></h3>

$\bold{(4-2x)^{4} }$

$\bold{[(4-2x)^{2}]^{2} }$

$\bold{(4-2x)^{2}(4-2x)^{2} }$

goblinko [34]2 years ago

5 0

$\huge\mathfrak\pink{Answer}$

(4 - 2x) ²

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Please help me and can you explain thank you

Rufina [12.5K]

Answer:

(4,2), there is already a 4 in x value

Step-by-step explanation:

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2 years ago

What is the mixed number for 56/10

andre [41]

Well, 10 can go into 56, 5 times, so your whole number would be 5.
Then 50 (where did i get 50 from? 5 times the ten is 50) minues 56 is 6. So it would be :
5 and 6/10 (your denominator stays the same)
But it needs o be simplafied to its lowest terms. They are both divisable by 2, SOO 6 divided by 2 is 3, and 10 divided by 2 is 5 So, your new fraction is:
5 and 3/5 in which it cant be simplafied anymore.
<em>~ 5 3/5 </em><em>is your answer :)</em>

4 0

3 years ago

Answer fast but correctly

olasank [31]

${m}^{2} - n \\ Given, \: \: m = 3 \: \: n = 2, then, \\ \: \: {(3)}^{2} - 2 \\ = 9 - 2 \\ = 7$

<u>Answer</u><u>:</u>

<u>a.</u><u> </u><u>7</u>

Hope you could understand.

If you have any query, feel free to ask.

3 0

2 years ago

Read 2 more answers

What quadrant is 300π/276 in?<br><br> Can u solve these too plz

Step2247 [10]

Answer:

3

Step-by-step explanation:

If the angle is greater than 360°, subtract 360° until the angle is less than 360°

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2 years ago

Solve the rational function of (check image) and check for extraneous solutions

Oxana [17]

Answer:

Option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

Step-by-step explanation:

Given the expression

$\frac{5}{x}=\frac{4x+1}{x^2}$

Solving the rational function

$\frac{5}{x}=\frac{4x+1}{x^2}$

Apply fraction across multiply: if $\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5x^2=x\left(4x+1\right)$

Subtract x(4x+1) from both sides

$5x^2-x\left(4x+1\right)=x\left(4x+1\right)-x\left(4x+1\right)$

Simplify

$5x^2-x\left(4x+1\right)=0$

5x² - 4x² - x = 0

x² - x = 0

Factor x² - x = x(x-1)

so

x(x-1) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

$x=0\quad \mathrm{or}\quad \:x-1=0$

Thus, the solution to the equation is:

$x=0,\:x=1$

But, it is clear that if we substitute x = 0, the equation becomes undefined because we can not have the denominator to be 0.

In other words, the equation is undefined for x = 0

Thus, x = 0 is an extraneous solutions.

Therefore, option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

5 0

3 years ago