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3 years ago

Is the fraction 1/3 equivalent to a terminating decimal or a decimal that does not terminate?

Mathematics

2 answers:

Bogdan [553]3 years ago

5 0

your answer is 0.33333333333333 and so on

devlian [24]3 years ago

4 0

Its a recurring decimal that does not terminate

1/3 = 0.3333333.......

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Find the zeros of the polynomial function.

Ahat [919]

◆ QUADRATIC EQUATIONS ◆

$given \: equation \: is \: , \\ \\ {x}^{2} - 12x + 20 = 0 \\ \\ using \: quadratic \: formula \: , \\ \\ x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \: \: \: \: = \frac{ - ( - 12) + \sqrt{ { (- 12)}^{2} - 4(1)(20) } }{2(1)} \\ \\ x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \: \: \: \: = \frac{ - ( - 12) - \sqrt{ { (- 12)}^{2} - 4(1)(20) } }{2(1)} \\ \\ x = \frac{12 + 8}{2} \: \: \: \: \: or \: \: \: \: x = \frac{12 - 8}{2} \\ \\ x = 10 \: \: \: \: \: or \: \: \: \: \: x = 2 \: \: \: ans.$

8 0

3 years ago

Rodger has 47 cars . Can he group the cars in more than two ways?

deff fn [24]

First of all, Rodger must be making some serious cash to have 47 cars. Going back to the question, he can not group the cars in more than 2 ways. He can only group it in 1 way, 47 groups of 1. Pls brainliest

4 0

3 years ago

Sally makes $9.15 per hour. If she works 3.5 hours, how much money will she make?

liraira [26]

Answer:

$12.65

Step-by-step explanation:

i caculated that

5 0

3 years ago

Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar

klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

$CI(\mu)=\lbrack28.94,31.06\rbrack$

4 0

1 year ago

Find f(-4) <br> if f(x) = {(2,-4), (4,0), (5,-4), (-4, 0)}

Troyanec [42]

Answer:

If f(x) = 2x2 - 4x + 3 evaluate for f(3) and f(-4) 2. g(x) = V - 2x; find g(-27) and g(-1) ... {(-3,0), (+3, 3),(-3,2)} ... If f(x) = 5x+5, find and simplify f(4).

8 0

3 years ago