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allsm [11]
3 years ago
10

Alan has two more than twice as many chocolates as does alice, and half as many chocolates as does nadia. if alice has ‘a' numbe

r of chocolates, then in terms of ‘a', how many chocolates do alan, alice and nadia have
Mathematics
1 answer:
Misha Larkins [42]3 years ago
5 0
Alan has two more than twice as many chocolates as does alice
Alan = 2Alice + 2 ----(1)

Alan has half as many chocolates as does nadia
Alan = 1/2 Nadia
so Nadia = 2Alan ----(2)

if Alice has 'a' number of chocolates
from (1)
Alan = 2a + 2 ----(3)
from (2) and (3)
Nadia = 2 (2a+2) = 4a+4 ----(4)

So Alan Alice and Nadia have
(2a+2) + a + (4a+4) = 7a+ 6 #
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REY [17]

Answer:

The answer is 1

Step-by-step explanation:

2(a+7)−7=9

Step 1: Simplify both sides of the equation.

2(a+7)−7=9

(2)(a)+(2)(7)+−7=9(Distribute)

2a+14+−7=9

(2a)+(14+−7)=9(Combine Like Terms)

2a+7=9

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Step 2: Subtract 7 from both sides.

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Step 3: Divide both sides by 2.

2a

2

=

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