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allsm [11]
3 years ago
10

Alan has two more than twice as many chocolates as does alice, and half as many chocolates as does nadia. if alice has ‘a' numbe

r of chocolates, then in terms of ‘a', how many chocolates do alan, alice and nadia have
Mathematics
1 answer:
Misha Larkins [42]3 years ago
5 0
Alan has two more than twice as many chocolates as does alice
Alan = 2Alice + 2 ----(1)

Alan has half as many chocolates as does nadia
Alan = 1/2 Nadia
so Nadia = 2Alan ----(2)

if Alice has 'a' number of chocolates
from (1)
Alan = 2a + 2 ----(3)
from (2) and (3)
Nadia = 2 (2a+2) = 4a+4 ----(4)

So Alan Alice and Nadia have
(2a+2) + a + (4a+4) = 7a+ 6 #
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makvit [3.9K]

Answer:

-9x² + 25

Step-by-step explanation:

To solve, use FOIL. FOIL:

First

Outside

Inside

Last

Solve "First":

(3x)(-3x) = -9x²

Solve "Outside":

(3x)(-5) = -15x

Solve "Inside":

(-5)(-3x) = +15x

Solve "Last":

(-5)(-5) = +25

Combine like terms:

-9x² - 15x + 15x + 25

-9x² (-15x + 15x) + 25

-9x² + 25

-9x² + 25 is your answer.

~

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andrew-mc [135]

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Step-by-step explanation:

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Jennifer was baking cupcakes for her class. She needed to bake 35 cupcakes in all. Each cupcake needed .13 cups of sugar. How ma
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Answer and working out attached below. Hope it helps

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