Alan has two more than twice as many chocolates as does alice, and half as many chocolates as does nadia. if alice has ‘a' numbe
r of chocolates, then in terms of ‘a', how many chocolates do alan, alice and nadia have
1 answer:
Alan has two more than twice as many chocolates as does alice
Alan = 2Alice + 2 ----(1)
Alan has half as many chocolates as does nadia
Alan = 1/2 Nadia
so Nadia = 2Alan ----(2)
if Alice has 'a' number of chocolates
from (1)
Alan = 2a + 2 ----(3)
from (2) and (3)
Nadia = 2 (2a+2) = 4a+4 ----(4)
So Alan Alice and Nadia have
(2a+2) + a + (4a+4) = 7a+ 6 #
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