Alan has two more than twice as many chocolates as does alice, and half as many chocolates as does nadia. if alice has ‘a' numbe
r of chocolates, then in terms of ‘a', how many chocolates do alan, alice and nadia have
1 answer:
Alan has two more than twice as many chocolates as does alice
Alan = 2Alice + 2 ----(1)
Alan has half as many chocolates as does nadia
Alan = 1/2 Nadia
so Nadia = 2Alan ----(2)
if Alice has 'a' number of chocolates
from (1)
Alan = 2a + 2 ----(3)
from (2) and (3)
Nadia = 2 (2a+2) = 4a+4 ----(4)
So Alan Alice and Nadia have
(2a+2) + a + (4a+4) = 7a+ 6 #
You might be interested in
It was 65 degrees by lunch time.
Answer:
19
Step-by-step explanation:
40-21+19
Answer:
[2,6]
Step-by-step explanation:
3x+5y=36
5x-4=y
3x+5(5x-4)=36
3x+25x-20=36
28x-20=36
28x=56
x=2
5x-4=y
5*2-4=y
10-4=y
6=y
the answer issss −
1.9
b
+
7.8
She was paid 649.60 because 20% of $1,123 is %224.6