Answer:
Well, you could always just put it onto a scale to find the mass. But assuming you aren't talking about a laboratory setting. sorry if its all werid i cant really put it into how it supposed to be
The general formula is:
ρ
=
m
V
where
ρ
is density in
g/mL
if mass
m
is in
g
and volume
V
is in
mL
.
So to get the mass...
m
=
ρ
V
Or to get the volume...
V
=
m
ρ
When you have the volume and not the density, and you want to find mass, you will need to find the density yourself. It's often readily available on the internet.
Just replace "[...]" with the object you want, and if it's not exactly what you need, consider it an estimate.
These days, you should be able to search for the density of any common object.
When you have the density and volume but not the mass, then just make up a mass.
You shouldn't need specific numbers to do a problem. You can always solve a problem in general and get a solution formula. If you need to, just make up some numbers that you know how to use.
Step-by-step explanation:
Area = pi × r²
144 pi cm² = pi × r²
144 pi ÷ pi = r 2
root 144 = r
12 cm = r
diameter = 2r = 2(12) = 24 cm
Answer:
175/3 or 58.333...
Step-by-step explanation:
This is fairly complicated but I will try to make it as simple as possible. I also apologize in advance for how impossible it is to make fractions look like fractions. I also had to insert a bunch of unnecessary parentheses just because the fractions that I can make are relatively inaccurate.
The distance between 2 cities can be represented as d.
Time is d/r if r is rate, so B->NY=d/50
Similarly,NY->B is d/70
Obviously the average speed is 2d/(d/50+d/70), this is just an average time
Now just remove the d and get (d/d)*2/(1/50+1/70)
You can now multiply by the LCM/LCM, which is 350/350.
After calculating you will get 700/12 which is 58.333...(This is how to enter into your RSM browser) Hope this helps. Sorry it is so late.
Answer:
See explanation
Step-by-step explanation:
Consider triangles ABC and DEC. In these triangles,
- given
- given;
as vertical angles.
So,
by SAS postulate (two sides and angle between these sides of one triangle are congruent to two sides and angle between these sides of another triangle, so triangles are congruent).
Congruent triangles have congruent corresponding parts, hence,
