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Vaselesa [24]
3 years ago
10

How do you find a volume of a cube and Rectangular prism and a cylinder? PLEASE HELP ASAP ASAP PLEASSEEEEEEE I BEG YOU

Mathematics
2 answers:
Nat2105 [25]3 years ago
5 0

Of course!

Cube: side length * side length * side length

So if it's a 6x6x6 cube, it's 6*6*6 = 216

Rectangular Prism: side length * side height * base width

So if it's a 6x7x8 prism, it's 6*7*8 = 336

Cylinder: π * (radius squared) * height

So if the base's radius is 6 and the height is 7, it's π*6^2*7 = 252π

Maksim231197 [3]3 years ago
3 0
So basically u just measure side by side length and basically kinda do it the same way u would measure the area of a 2D shape. formula: volume =side side side
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Find the missing side length to the nearest tenth of a millimeter.
wel

Answer:

17.9

Step-by-step explanation:

3.7²+17.5²=319.94

\sqrt{319.94\\= 17.9

8 0
3 years ago
Which gives the correct values for points A, B, C, and D?
saveliy_v [14]

Answer:

<em>The correct answer is: A</em>

Step-by-step explanation:

<u>Points on a Numeric Line</u>

The numeric line shown in the figure has four points A, B, C, and D. It's clear that each marked division of the line has a value of 1/4 units and all four points are below the reference zero, thus all are negative.

Point A is clearly on the -2 mark, thus

A=-2

Point B is one mark above A, thus it's located at:

B=-2+\frac{1}{4}=-\frac{7}{4}=-1\frac{3}{4}

B=-1\frac{3}{4}

Point C is one mark below -1, thus:

C=-1-\frac{1}{4}=-1\frac{1}{4}

Finally, point D is one mark below 0:

D=-\frac{1}{4}

The correct answer is: A

5 0
3 years ago
Plese tell how to solve this​
klasskru [66]

Answer:

hope you understand the answers

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%20%5Ctimes%20%20%5Cfrac%7B2%7D%7B3%7D%20%20%3D%201%20%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%20" id
Ulleksa [173]
The answer : x= one half
6 0
3 years ago
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=2−x2. What are the dimensions of su
Paul [167]

Answer:

Step-by-step explanation:

Given that a rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

y=2-x^2

the parabola is open down with vertex at (0,2)

We can find that the rectangle also will be symmetrical about y axis.

Let the vertices on x axis by (p,0) and (-p,0)

Then other two vertices would be (p,2-p^2) (-p,2-p^2) because the vertices lie on the parabola and satisfy the parabola equation

Now width = 2-p^2

Area = l*w = 2(2p-p^3)

Use derivative test

I derivative = 2(2-3p^2)

II derivative = -12p

Equate I derivative to 0 and consider positive value only since we want maximum

p = \sqrt{\frac{2}{3} }

Thus width= \sqrt{\frac{2}{3} }

Length =2\sqrt{\frac{2}{3} }

Width = 2-2/3 = 4/3

3 0
3 years ago
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