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Anastasy [175]
3 years ago
12

Students in Mrs. Burn's science class used scales to measure the mass, in grams, of a solid. The mass of

Mathematics
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

Mean

Step-by-step explanation:

Finding the mean, or the average, of the different weights that were measured, would best estimate the true mass of the solid.

This would find the average mass, which would be the most accurate estimate of the solid's actual mass.

Using the minimum, maximum, and mode will not take into account the other weights that were measured. This makes it much more inaccurate.

So, the correct answer is Mean.

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The numbers of cars (c) in the parking lot increases when the parking fee (f) decrease. Write the correct equation for this scen
vodka [1.7K]
So when one goes up, the other goes down. This is an inverse equation.

An inverse equation looks like this: y = 1/x

In this case, when parking fee (f) decreases, cars (c) increase.
You know which side to put each variable on using the chart they gave you.
f         | c
20.00  15        (20.00 = x/15) x=300
30.00  10        (30.00 = x/10) x=300

So your equation in this case is f = 300/c
Knowing that, plug in the fee of 6.00

6 = 300/c   Multiply both sides by c.
6c = 300    Divide both sides by 6.
c = 50 cars

5 0
3 years ago
A loaf of sandwich bread contains 24 slices. Which of these tables correctly shows the ratios of different numbers of loaves of
noname [10]

Answer:

15

Step-by-step explanation: i'm not explaining why

5 0
3 years ago
What is the solution 6x-4 =2(3x-2)
Lapatulllka [165]

Answer:

x= 0

Step-by-step explanation:

6x-4=2(3x-2)

or,6x-4=6x-4

or,x=o

8 0
3 years ago
Formal Asses
Lostsunrise [7]
That’s is so impressive dude ngl
5 0
3 years ago
If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a
harkovskaia [24]

Given:

The function is:

h(x)=x^2-3x+5

To find:

The value of h(2x+1).

Solution:

We have,

h(x)=x^2-3x+5

Putting x=2x+1, we get

h(2x+1)=(2x+1)^2-3(2x+1)+5

h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5

h(2x+1)=4x^2+4x+1-6x-3+5

On combining like terms, we get

h(2x+1)=4x^2+(4x-6x)+(1-3+5)

h(2x+1)=4x^2-2x+3

Therefore, the required function is h(2x+1)=4x^2-2x+3.

3 0
3 years ago
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