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larisa [96]
3 years ago
11

PLZ!!!!HELP!!!What is the absolute deviation for 15 in the data set?

Mathematics
2 answers:
choli [55]3 years ago
6 0

Answer: the absolute deviation for 15 is 10

Step-by-step explanation:

Brut [27]3 years ago
5 0
20 + 20 + 30 + 15 + 40 = 125
125/5= 25
25-15 = 10
Absolute deviation for 15 is 10
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Answer:

5 should be correct answer

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_______ is 100 times as much as 90
jek_recluse [69]

90*100=9000

hope that helps

3 0
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Find x! Please help!!
a_sh-v [17]

{(8 + x)}^{2}  =  {8}^{2}  +  {15}^{2}  \\ {(8 + x)}^{2}  =  64  +  225 \\  {(8 + x)}^{2}  = 289 \\ {(8 + x)}^{2}  =  {17}^{2}  \\ 8 + x = 17 \\ so \: x = 17 - 8 = 9
5 0
3 years ago
I need Help please help with X - 7.6 = 18.2
nalin [4]

Answer:

x = 25.8

Step-by-step explanation:

  1. Add 7.6 to each side, so it now looks like this: x = 25.8

I hope this helps!

8 0
3 years ago
A bag contains 4 white,5 blacks and 2 blue balls. 3 balls are drawn one after the other without replacement from the bag .what i
Doss [256]

Answer:

24/99

Step-by-step explanation:

From the question given above, the following data were obtained:

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

Probability that they are of different color =?

Next, we shall determine the total number of balls in the bag. This can be obtained as follow:

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

TOTAL = 4 + 5 + 2 = 11 balls

Next, we shall determine the possible outcome of draw. This can be obtained as follow.

The possible outcome could be:

WBLB or WBBL or BBLW or BWBL or BLBW or BLWB

Next we shall determine the probability of each of outcomes.

Since the ball is drawn without replacement, it means the total number of ball will reduce after each draw.

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

TOTAL = 11

P(WBLB) = 4/11 × 2/10 × 5/9 = 40/990

P(WBLB) = 4/99

P(WBBL) = 4/11 × 5/10 × 2/9 = 40/990

P(WBBL) = 4/99

P(BBLW) = 5/11 × 2/10 × 4/9 = 40/990

P(BBLW) = 4/99

P(BWBL) = 5/11 × 4/10 × 2/9 = 40/990

P(BWBL) = 4/99

P(BLBW) = 2/11 × 5/10 × 4/9 = 40/990

P(BLBW) = 4/99

P(BLWB) = 2/11 × 4/10 × 5/9 = 40/990

P(BLWB) = 4/99

Finally, we shall determine the probability that they are of different color. This can be obtained as follow:

P(WBLB) = 4/99

P(WBBL) = 4/99

P(BBLW) = 4/99

P(BWBL) = 4/99

P(BLBW) = 4/99

P(BLWB) = 4/99

Probability that they are of different color =?

Probability that they are of different color = P(WBLB) + P(WBBL) + P(BBLW) + P(BWBL) + P(BLBW) + P(BLWB)

= 4/99 + 4/99 + 4/99 + 4/99 + 4/99 + 4/99

= (4 + 4 + 4 + 4 + 4 + 4)/99

= 24/99

Thus, the probability that they are of different color is 24/99

4 0
3 years ago
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