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lara [203]
3 years ago
11

A plumber had a pipe that was 2 yards long he cut 18 inches off the end of the pipe

Mathematics
1 answer:
balandron [24]3 years ago
7 0
To convert yards to feet, you would multiply it by 3. So, since there the pipe is 2 yards long, you could multiply 2*3 to get 6 feet. Then you can convert feet to inches by multiplying it by 12. 6*12 is equal to 72, so 2 yards is equal to 72 inches. Lastly, you can subtract 18 from 72, to get 54, and 54 inches would be your final answer.
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1.) What is m∠PTS?<br><br> 2.) What is the value of x?
RoseWind [281]
STR and QTP are both equal 180
so PTS +PTR=180 andQTR+PTR=180 which means
PTS=QTR(for a shorter explanation they are staying against each other in a line cross

11y-110=4y-5
7y=105
y=105:7
y=15 grafe which means
PTS
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Hurry 50 points for correct answer
Ad libitum [116K]

Answer: <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

Step-by-step explanation:

The equation x=\sqrt{6x+7} can be solved by squaring both sides:

x^2 = 6x + 7\\\\x^2 - 6x - 7 = 0\\\\(x-7)(x+1) = 0

We can see that -1 and 7 are solutions, but make sure they are not extraneous by substituting them in the original equation:

1 = \sqrt{-1}\\ 7 = \sqrt{49}

The square root of 49 equals 7, but the square root of -1 is an imaginary number.

The correct choice is <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

4 0
3 years ago
What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36
GREYUIT [131]
ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

f(x) = {x}^{4} - 13 {x}^{2} + 36

To find the real roots, we equate the function to zero to obtain;

{x}^{4} - 13 {x}^{2} + 36 = 0

We can solve this equation as a quadratic equation in
{x}^{2}.

Thus we rewrite the equation as,

({x}^{2})^{2} - 13 {x}^{2} + 36 = 0

We split the middle term to get,

({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.

We factor to get,

{x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0

We factor to get,

( {x}^{2} - 9)( {x}^{2} - 4) = 0

Either

{x}^{2} - 9 = 0
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{x}^{2} - 4 = 0

x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}
x = \pm3 \: or \: x = \pm2

x=-3,-2,2,3

The correct answer is A
5 0
3 years ago
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