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3 years ago

A plumber had a pipe that was 2 yards long he cut 18 inches off the end of the pipe

1 answer:

7 0

To convert yards to feet, you would multiply it by 3. So, since there the pipe is 2 yards long, you could multiply 2*3 to get 6 feet. Then you can convert feet to inches by multiplying it by 12. 6*12 is equal to 72, so 2 yards is equal to 72 inches. Lastly, you can subtract 18 from 72, to get 54, and 54 inches would be your final answer.

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1.) What is m∠PTS? 2.) What is the value of x?

RoseWind [281]

STR and QTP are both equal 180
so PTS +PTR=180 andQTR+PTR=180 which means
PTS=QTR(for a shorter explanation they are staying against each other in a line cross

11y-110=4y-5
7y=105
y=105:7
y=15 grafe which means
PTS
y*4-5=55 grade

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3 years ago

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Marking BRAINLYEST need help ASAP

Andrei [34K]

Answer:

Step-by-step explanation:

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3 years ago

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Jackson has a gift card for $120 to use at a department store. He wants to purchase 2 shirts and 3 pairs of pants with his gift

garri49 [273]

The answers is A because it shows the domain: 0 is less than or equal to x and less that on equal to 60

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3 years ago

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Hurry 50 points for correct answer

Ad libitum [116K]

Answer: "7 is a solution to the original equation. The value –1 is an extraneous solution."

Step-by-step explanation:

The equation $x=\sqrt{6x+7}$ can be solved by squaring both sides:

$x^2 = 6x + 7\\\\x^2 - 6x - 7 = 0\\\\(x-7)(x+1) = 0$

We can see that -1 and 7 are solutions, but make sure they are not extraneous by substituting them in the original equation:

$1 = \sqrt{-1}\\ 7 = \sqrt{49}$

The square root of 49 equals 7, but the square root of -1 is an imaginary number.

The correct choice is "7 is a solution to the original equation. The value –1 is an extraneous solution."

4 0

3 years ago

What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36

GREYUIT [131]

ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

$f(x) = {x}^{4} - 13 {x}^{2} + 36$

To find the real roots, we equate the function to zero to obtain;

${x}^{4} - 13 {x}^{2} + 36 = 0$

We can solve this equation as a quadratic equation in
${x}^{2}.$

Thus we rewrite the equation as,

$({x}^{2})^{2} - 13 {x}^{2} + 36 = 0$

We split the middle term to get,

$({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.$

We factor to get,

${x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0$

We factor to get,

$( {x}^{2} - 9)( {x}^{2} - 4) = 0$

Either

${x}^{2} - 9 = 0$
or

${x}^{2} - 4 = 0$

$x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}$
$x = \pm3 \: or \: x = \pm2$

$x=-3,-2,2,3$

The correct answer is A

5 0

3 years ago

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