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3 years ago

When graphed, the circle with equation x2 + y2 - 10x + 16 = 0 will lie ENTIRELY in Quadrants...

Mathematics

2 answers:

Trava [24]3 years ago

5 0

The answer is Quadrants 1 and 4

Alla [95]3 years ago

3 0

Its I and IV :).kbiyhtrhirthrkhnrihrthn

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For the pair of points find the distance between them and the midpoint of the line segment joining them.(720,50), (125,18)The di

Lana71 [14]

Given two points

$(x_1,y_1)$

and

$(x_2,y_2)$

The distance between them is >>>

$D=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}$

The points given are (Sqrt(20), Sqrt(50)) and (Sqrt(125), Sqrt(8)), so their distance is >>>

$\begin{gathered} D=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ D=\sqrt[]{(\sqrt[]{8}-\sqrt[]{50})^2+(\sqrt[]{125}-\sqrt[]{20})^2} \\ D=\sqrt[]{(\sqrt8)^2-2(\sqrt[]{8})(\sqrt[]{50})+(\sqrt[]{50})^2^{}+(\sqrt[]{125})^2-2(\sqrt[]{125})(\sqrt[]{20})+(\sqrt[]{20})^2} \\ D=\sqrt[]{8-2(2\sqrt[]{2})(5\sqrt[]{2})+50+125-2(5\sqrt[]{5})(2\sqrt[]{5})+20} \\ D=\sqrt[]{8-40+50+125-100+20} \\ D=\sqrt[]{63} \\ D=3\sqrt[]{7} \end{gathered}$

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The midpoint formula is >>>

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Plugging in the points, we have >>>

$\begin{gathered} M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ M=(\frac{\sqrt[]{20}+\sqrt[]{125}}{2},\frac{\sqrt[]{50}+\sqrt[]{8}}{2}) \\ M=(\frac{2\sqrt5+5\sqrt[]{5}}{2},\frac{5\sqrt[]{2}+2\sqrt[]{2}}{2}) \\ M=(\frac{7\sqrt[]{5}}{2},\frac{7\sqrt[]{2}}{2}) \end{gathered}$

3 0

2 years ago

What statement about the product is true? 5.5•√5

Kryger [21]

The product is irrational. a rational number (5.5) times an irrational one (√5) is always irrational

7 0

4 years ago

If ab = 9 and a² + b² = 81, then (a+b)² = ?

Andre45 [30]

Answer:

Step-by-step explanation:

Through some clever algebra, we can combine our first two equations using the fact that

$(a+b)^2=a^2+2ab+b^2$

We have the a² and the b² in the equation $a^2+b^2=81$ , and we <em>almost </em>have a 2ab in the equation $ab=9$ . To get that 2ab, we can simply double both sides of the first equation to get $2ab=18$ . From there, we'll add the first two equations together, giving us the summed equation

$a^2+b^2+2ab=81+18\\a^2+2ab+b^2=99$

And since $(a+b)^2=a^2+2ab+b^2$ , we can equivalently say that

$(a+b)^2=99$

5 0

3 years ago

Rebecca works at a store that sells clothing accessories. The supply function for pairs of socks is P = Q - 13, where P is the p

stepladder [879]

The quantity is 19 from the solution in the image

7 0

4 years ago

Which expression is equivalent to the expression (x^2-y^2)^2

Pepsi [2]

Step-by-step explanation:

$(x^2-y^2)^2\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=(x^2)^2-2(x^2)(y^2)+(y^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=x^4-2x^2y^2+y^2\\-----------------------------$

$\text{Other solution}\\\\(x^2-y^2)^2\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\= [(x-y)(x+y)]^2\\\\\text{use}\ (ab)^n=a^nb^n\\\\=(x-y)^2(x+y)^2$

7 0

3 years ago