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Marina86 [1]
2 years ago
13

The reserve capacities (in hours) of 18 randomly selected automotive batteries are listed. Use a 99% level of confidence. (Adapt

ed from Consumer Reports) 1.70 1.60 1.94 1.58 1.74 1.60 1.86 1.72 1.38 1.46 1.64 1.49 1.55 1.70 1.75 0.88 1.77 2.07
Mathematics
1 answer:
BartSMP [9]2 years ago
7 0

Answer:

99% confidence interval is (1.75, 5.61)

Step-by-step explanation:

From the data above, mean is 3.68 and sd is 2.06. n = 18, degree of freedom = n-1 = 18-1 = 17. t-value corresponding to 17 degrees of freedom and 99% confidence level is 3.965

Confidence Interval (CI) = mean + or - (t×sd)/√n

CI = 3.68 + (3.965×2.06)/√18 = 3.68 + 8.1679/4.243 = 3.68 + 1.93 = 5.61

CI = 3.68 - (3.965×2.06)/√18 = 3.68 - 8.1678/4.243 = 3.68 - 1.93 = 1.75

99% confidence interval is (1.75, 5.61)

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Convert 5 2/5 into an improper fraction ​
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Which of the following describes the translation of the graph of y = x2 to obtain the graph of y = -x2 - 3?
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reflections across the x axis and a shift down 3 units

Step-by-step explanation:

y = x^2

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5 0
3 years ago
What is the equation that represents the sequence in this problem ? Find the price after the 8th month
AVprozaik [17]

ANSWER

\begin{gathered} a_n=ar^{n\text{ - 1}} \\ a_8\text{ = \$38.26} \end{gathered}

EXPLANATION

The problem represents a geometric progression.

The general form of a geometric sequence is:

a_n=ar^{n\text{ - 1}}

where a = first term

r = common ratio

The first term from the table is the first price (for the first month). That is $80.00

To find the common ratio, we divide a term by its preceeding term.

Let us divide the price of the second month from the first.

We have:

\begin{gathered} r\text{ = }\frac{72}{80} \\ r\text{ = 0.9} \end{gathered}

The price after the 8th month is the value of a(n) when n = 8

So, we have that:

\begin{gathered} a_8\text{ = 80 }\cdot0.9^{(8\text{ - 1)}} \\ a_8\text{ = 80 }\cdot0.9^7 \\ a_8\text{ = \$38.26} \end{gathered}

5 0
9 months ago
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