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n200080 [17]
3 years ago
8

Can the set of lengths be the side lengths of a right triangle? 18 m, 24 m, 30 m

Mathematics
1 answer:
elena55 [62]3 years ago
7 0
 - - 18 m, 24 m, 30 m Can indeed set the lengths of a right triangle.
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Can the numbers 24, 32, 40 be the lengths of the three sides of a right triangle? Explain why or why not.
nlexa [21]
Yes they can bc they are all odd
7 0
3 years ago
If Julie had 10 bags of apples that has 5 apples in it and she took out 3 apples from 1 bag, how many apples does she have
miv72 [106K]

Answer:

47 apples

Step-by-step explanation:

50 apples - 3 apples

47 apples

7 0
3 years ago
Read 2 more answers
Out of seniors at a local high school, 60% went on the senior trip. At the hotel , one room was reserved for every 4 students .
sweet [91]

Answer:

<u>Number of rooms reserved for the students are - 90 .</u>

Step-by-step explanation:

Firstly ,

As we know 60% of the 600 students went on the trip,

Then ,

Number of students went on the trip = 60% of 600

                                                          = \frac{60}{100}\times600

                                                        = 360

Now ,

Given - One room is reserved  for 4 students ,

Therefore , Number of rooms for 360 students = \frac{360}{4}

                                                                             = 90

<u>Hence , the answer is  90 rooms reserved for the students.</u>

7 0
3 years ago
HELP PLEASE WILL MARK BRAINLIEST!!
Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

from \: the \: figure \\ AB = 300 \: ft \:  \:  \: angle \: C = 60  \:( theta)\: degress \\ in \: triangle \: ABC \: using \:  tan \: theta\\  \tan(60)  =  \frac{opposite \: side}{adjacent \: side}  \\  \tan(60)  =  \frac{300}{BC}  \\  \sqrt{3}  =  \frac{300}{BC}  \\ BC =  \frac{300}{ \sqrt{3} }  \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\   \tan(30 )  =\frac{opposite \: side}{adjacent \: side} \\  \tan(30)   =  \frac{300}{BD}  \\  \frac{1}{ \sqrt{ 3} }  =  \frac{300}{BD}  \\ BD = 300 \sqrt{3}  \\ CD = BD - BC \\  = 300 \sqrt{3 }  - 100 \sqrt{3}  \\  = (300 - 100) \sqrt{3}  \\  = 200 \sqrt{3 }  \\  = 200 \times 1.732 \\  = 346.4 \: ft

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

7 0
3 years ago
Solve for q q+5/4=-2
Kay [80]

Answer: q = -13

Step-by-step explanation:

(q+5)/4 = -2 first you multiply 4 to remove denominators

(q+5) = -8 then subtract 5

q = -13

4 0
3 years ago
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