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Andrew [12]
3 years ago
13

Suppose you know the perimeter of n octagons arranged as shown. What would you do to find the perimeter if 1 more octagon was ad

ded?

Mathematics
1 answer:
kogti [31]3 years ago
3 0

As shown in the figures given :

For Figure 1 : perimeter = 8 units   [As can be seen in the figure]

For figure 2(with 2 octagons) : perimeter = 8 × 2 - 1 = 15 units    [since 1 side is common ]

For figure 2(with 3 octagons) : perimeter = 8 × 3 - 2 = 22 units  [since 2 sides is common ]

If one more octagon is added

then perimeter = 8 × 4 - 3 = 29 units    [since 3 sides will be common ]


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Step-by-step explanation:

This is already factored for the zeros of the quadratic.  If x - 5 = 0 and x - 20 = 0 then x = 5 and 20.  The ball was kicked 5 feet out and landed at 20 feet down the field.  The difference is 15 feet.  That's how far the ball traveled from its initial position on the ground to its landing place.

So 15 feet from where it was kicked.

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1. 2x+5(6x-9)=179<br>2. -40=6x-5(-4x-18)<br>solve for X​
pav-90 [236]

Answer:

1. x = 7

2. x = -5

Step-by-step explanation:

1. Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation: 2*x+5*(6*x-9)-(179)=0

Pull out like factors  6x - 9  =   3 • (2x - 3)

 (2x +  15 • (2x - 3)) -  179  = 0

Pull out like factors: 32x - 224  =   32 • (x - 7)

Solve: x-7 = 0

Add  7  to both sides of the equation  = 7

2. Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation: -40-(6*x-5*(-4*x-18))=0

Pull out like factors: -4x - 18  =   -2 • (2x + 9)

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Pull out like factors:  -26x - 130  =   -26 • (x + 5)

-26 • (x + 5)  = 0

Solve: x+5 = 0

Subtract  5  from both sides of the equation: x = -5

Hope this helps! Please mark as brainliest.

Thanks!

5 0
2 years ago
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