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professor190 [17]
2 years ago
5

Certain flightness beetles havw wing​

Mathematics
1 answer:
Doss [256]2 years ago
3 0

Answer:

yes. but they cant fly cuz the wings are jus for show or too scare predaters

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If p is the hypothesis of a conditional statement and q is the conclusion, which is represented by ~p → ~q?
Bogdan [553]
It is equivalent to q -> p. 
4 0
2 years ago
What is 5 times three fourths
Hatshy [7]
When multiplying with fractions you can multiply the top and the bottom independantly
5*3 = 15
1*4 = 4

so 5 * (3/4) = 15/4
6 0
3 years ago
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The diffrence between an integer p and (-5) is 1 find the value of p ​
Nastasia [14]

Solution:

<u>Note that:</u>

  • Given sentence: The difference between an integer p and (-5) is 1.

<u>Let's reread the sentence carefully.</u>

The difference between an integer p and (-5) is 1.

  • => p - (-5) = 1

<u>Change the sign.</u>

  • p - (-5) = 1
  • => p + 5 = 1

<u>Subtract 5 both sides:</u>

  • p + 5 = 1
  • => p + 5 - 5 = 1 - 5
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4 0
2 years ago
Why are the solutions to the proportions 40/8 = x/10 and x/40 = 10/8 the same?
romanna [79]

Answer:

Both proportions are equivalent.

Step-by-step explanation:

We have been given two proportions \frac{40}{8}=\frac{x}{10} and \frac{x}{40}=\frac{10}{8}. We are asked to find why the solutions to our given proportions are equal.

We can solve proportions by cross multiplying them.

After cross multiplying our both proportions we will get same equation that is:

40*10=8*x

400=8x

8*x=40*10

8x=400

Since we get same equation after cross multiplying both proportions, therefore, the solutions to the given proportions would be same.

4 0
3 years ago
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a fishbowl shaped like a sphere is filled with water. The fishbowl has a diameter of 16 inches. Which measurement is closest to
gregori [183]

Answer:

The volume of the water in the fishbowl is equal to

(682\frac{2}{3})\pi\ in^{3}  or  2,144.6\ in^{3}

Step-by-step explanation:

we know that

The volume of the sphere (a fishbowl) is equal to

V=\frac{4}{3}\pi r^{3}

In this problem we have

r=16/2=8\ in ----> the radius is half the diameter

substitute

V=\frac{4}{3}\pi (8^{3})=\frac{2,048}{3}\pi\ in^{3}

convert to mixed number

\frac{2,048}{3}\pi\ in^{3}=\pi (\frac{2,046}{3}+\frac{2}{3})=(682\frac{2}{3})\pi\ in^{3}

(3.14156)*(682\frac{2}{3})=2,144.6\ in^{3}

6 0
3 years ago
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