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2 years ago

What is 3/5 divided by 2 1/2 by the lowest quotient

Mathematics

1 answer:

Brilliant_brown [7]2 years ago

7 0

Answer:

Step-by-step explanation:

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Which shows the correct substitution of the values a, b, and c from the equation –2 = –x + x2 – 4 into the quadratic formula? Qu

Likurg_2 [28]

Answer:

a = 1

b = -1

c = -2

Step-by-step explanation:

We reorder the equation in such way that let us see the usual

ax² + bx + c = 0

Then the original quation is:

-2 = - x + x² - 4 ⇒ 0 = 2 - x + x² - 4 ⇒ x² - x - 2 = 0

Now we are able by simply inspection to identify a, b . c comparing our equation with the general equation so :

a = 1

b = -1

c = -2

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2 years ago

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Find the equation of the line shown!!!

-Dominant- [34]

Answer:

y=5/4x+4 is the equation

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2 years ago

Which of the following rational numbers is equal to 4 point 7 with bar over 7 ? (5 points) 43 over 9 , 49 over 9 , 35 over 9 , 3

jenyasd209 [6]

Answer:

43 over 9 is the fraction you are looking for.

Step-by-step explanation:

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2 years ago

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What is 2.75 times 8

Ann [662]

Answer:

the answer is 22

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2 years ago

Use Newton's method to approximate a root of the equation 3x^(7) + 2x^(4) + 2 = 0 as follows. Let x1 = 3 be the initial approxim

Maurinko [17]

Answer:

$x_{2}\approx 2.59, x_{4}\approx 4.3$

Step-by-step explanation:

1) Given that the formula for the Newton Method is:

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f(x_{n+1})}$

2) The Function and its 1st derivative

$f(x)=3x^{7}+2x^{4}+2\\f'(x)=21x^{6}+8x^{3}$

3) Let's work with the first approximation. Plugging in in the function:

$f(x)=3x^{7}+2x^{4}+2\Rightarrow f(3)=3(3)^{7}+2(3)^{3}+2\Rightarrow f(3)=6617\\f'(x)=21x^{6}+8x^{3}\Rightarrow f'(3)=21(3)^{6}+8(3)^{4}\Rightarrow f'(3)=15957\\\\x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\Rightarrow x_{2}=x_{1}-\frac{f(x_{1})}{f'(x_{1})}\\x_{2}=3-\frac{6617}{15957}\Rightarrow x_{2}\approx 2.59\\\\$

4) To approximate the other root x

$f(x)=3x^{7}+2x^{4}+2\Rightarrow f(5)=3(5)^{7}+2(5)^{3}+2\Rightarrow f(5)=234627\\f'(x)=21x^{6}+8x^{3}\Rightarrow f'(5)=21(5)^{6}+8(5)^{4}\Rightarrow f'(5)=333125\\\\x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\Rightarrow x_{4}=x_{3}-\frac{f(x_{1})}{f'(x_{1})}\\x_{4}=5-\frac{234627}{333125}\Rightarrow x_{4}\approx 4.3$

5 0

2 years ago