Answer:
C
Step-by-step explanation:
Since this is an indererminate form, use L'Hopital
d(sint)/dt = cos(t)
d[ln(2e^t) - 1] = (2e^t)/[2e^t - 1]
As t --> 0,
cos(0) = 1
(2e^t)/[2e^t - 1] = 2
1/2 is the limit
3 : 3 times 6 is 18, 2 times 9 is 18 and 3 times 3 is 9 plus 9 is 18
A+8/3 = 2/3
Or, (3a+8)/3 = 2/3 [taking LCM]
Or, 3a+8 = 2 [3 in both denominators are cancelled]
Or, 3a = 2-8
Or, a = -6/3
.•. a = -2,,
It’s a question because there is not value of time.
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