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irina [24]
2 years ago
10

Factor x3 + 3x2 + 2x completely. x(x2 + 3x + 2) x(x + 1)(x + 2) x(x - 1)(x - 2) DONE

Mathematics
2 answers:
Natasha2012 [34]2 years ago
6 0

\text{To factor out the expression, all of the numbers have to have the same}\\\text{amount of variables}\\\\\text{You would see that in the expression}\,\, x^3 + 3x^2 + 2x\,\,\text{they all}\\\text{have "x"}\\\\\text{Factor out x:}\\\\x^3 + 3x^2+2x\\\\x(x^2+3x+2)\\\\\text{Factor}\,\, x^3 + 3x^2+2x\\\\x(x+1)(x+2)\\\\\boxed{\text{Answer:}\,x(x+1)(x+2)}}

Likurg_2 [28]2 years ago
3 0

Answer:

<h2>x(x + 1)(x + 2)</h2>

Step-by-step explanation:

  x³ + 3x² + 2x

= x(x² + 3x + 2)  , notice that x is a common factor

= x(x + 1)(x + 2)

<u><em>Remark:</em></u><em> </em>(x + 1)(x + 2) = x² + 3x + 2  ; just develop

<u><em /></u>

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Step-by-step explanation:

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3 years ago
Students are running in a relay race. Each team will run a total of 3 miles. Each member of a team will run 1/8 of a mile. How m
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Answer:

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Step-by-step explanation:

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3 years ago
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Andrej [43]

Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.

Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

P(C) = (35+45)/300 = 80/300 = 8/30

P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

P(J | C) = 0.5625 = 0.56

2.)

P(C | J) = P(C n J) / P(J)

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P(C | J) = 0.6 = 0.60

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Step-by-step explanation:

I hope that help's

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