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irina [24]
3 years ago
10

Factor x3 + 3x2 + 2x completely. x(x2 + 3x + 2) x(x + 1)(x + 2) x(x - 1)(x - 2) DONE

Mathematics
2 answers:
Natasha2012 [34]3 years ago
6 0

\text{To factor out the expression, all of the numbers have to have the same}\\\text{amount of variables}\\\\\text{You would see that in the expression}\,\, x^3 + 3x^2 + 2x\,\,\text{they all}\\\text{have "x"}\\\\\text{Factor out x:}\\\\x^3 + 3x^2+2x\\\\x(x^2+3x+2)\\\\\text{Factor}\,\, x^3 + 3x^2+2x\\\\x(x+1)(x+2)\\\\\boxed{\text{Answer:}\,x(x+1)(x+2)}}

Likurg_2 [28]3 years ago
3 0

Answer:

<h2>x(x + 1)(x + 2)</h2>

Step-by-step explanation:

  x³ + 3x² + 2x

= x(x² + 3x + 2)  , notice that x is a common factor

= x(x + 1)(x + 2)

<u><em>Remark:</em></u><em> </em>(x + 1)(x + 2) = x² + 3x + 2  ; just develop

<u><em /></u>

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P+n=131p+3.26n=248.52
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Answer

Solution:

p = 79

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Step-by-step explanation:

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To solve for  p and n

Naming the first equation as A and second as B.

Using elimination method to solve.

In order to eliminate p we subtract equation A from B.

Subtracting A from B i.e [B-A

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Dividing both sides 2.26.

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∴ n=52

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p+52-52=131-52

∴ p=79

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