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3 years ago

Simple interest = P × r × t

Mathematics

1 answer:

kaheart [24]3 years ago

5 0

HOPE THIS WILL HELP U....

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Which expression is equivalent to (5m^)3

aleksklad [387]

Answer:

5m•5m•5m

Step-by-step explanation:

You are multiply the factor by itself as many times as the exponent says. so if the factor is 5m, you would multiply it by itself by the exponent, which in our case is 3.

8 0

3 years ago

Read 2 more answers

How to rationalize <img src="https://tex.z-dn.net/?f=%5Cfrac%7B17%7D%7B4%5Csqrt%7B1%7D7%20%7D" id="TexFormula1" title="\frac{17}

dem82 [27]

Answer:

$\frac{\sqrt{17}}{4}$

Step-by-step explanation:

Rationalizing the denominator of a fraction is when one multiplying fraction such that it removes any radical from the denominator. This can be done by multiplying both the numerator and the denominator by the radical that is present in the denominator. In fractional terms, a number over itself is equal to one, therefore, doing this would keep the equation true. After multiplying, one will simplify the resulting fraction.

$\frac{17}{4\sqrt{17}} * \frac{\sqrt{17}}{\sqrt{17}}\\\\= \frac{17\sqrt{17}}{4(17)}\\$

Simplify like factor found in both the numerator and the denominator,

$\frac{17\sqrt{17}}{4(17)}\\\\= \frac{\sqrt{17}}{4}$

8 0

3 years ago

What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

astraxan [27]

ANSWER

The value of the expression is
$- 1$

EXPLANATION

Method 1: Rewrite as product of
${i}^{2}$

The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
${i}^{2} = - 1$
to simplify the above expression.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times 1 \times 1 \times - 1 = - 1$

Method 2: Use indices to solve.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0 + 1 + 2 + 3 + 4}$

This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( {{i}^{2}} )^{5}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

8 0

3 years ago

Read 2 more answers

Which statements are true? Check all that apply. All rectangles are squares. All rhombi are parallelograms. All squares are rhom

Ede4ka [16]

Answer:

All rhombi are parallelograms.

All squares are rhombi.

No trapezoid is a rectangle.

6 0

3 years ago

How do i solve the square root problems?

Gwar [14]

You may want to elaborate on what you mean by "square root problems"

6 0

3 years ago