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noname [10]
3 years ago
13

Enter the correct value so that each expression is a perfect square trinomial

Mathematics
1 answer:
myrzilka [38]3 years ago
5 0

Answer:

Step-by-step explanation:

1). x² - 10x + a²

  By using the formula of (a - b)² = a² - 2ab + b²

  x² - 2(5)x + a²

  Therefore, for a perfect square of the expression a should be equal to 5.

  Therefore, (x² - 10x + 25) will be the answer.

2). x² + 2ax + 36

  = x² + 2(a)x + 6²

  For a perfect square of the given expression value of a should be 6.

   x² + 2(a)x + 6² = x² + 2(6)x + 6²

                           = (x + 6)²

  Therefore, x² + 12x + 36 will be the answer.

3). x^{2}+\frac{1}{2}x+a^2

    x^{2}+2(\frac{1}{4})x+a^2

   To make this expression a perfect square,

   a² = (\frac{1}{4})^2

   x^{2}+2(\frac{1}{4})x+(\frac{1}{4})^2 = (x+\frac{1}{4})^2

  Therefore, the missing number will be \frac{1}{16}.

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Answer:

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Step-by-step explanation:

To round to the nearest thousand, we need to look at the digit in the hundreds place, which is 6. Since 6 > 5, we know that we need to round up (because 6 is closer to 10 than it is to 0). Currently, the number is 95 thousand so when rounding up, the answer will be 96,000.

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(y - 2)2 = y2 – 6y + 4<br> Is this statement true or false?
trasher [3.6K]
<h3>Answer: False</h3>

==============================================

Explanation:

I'm assuming you meant to type out

(y-2)^2 = y^2-6y+4

This equation is not true for all real numbers because the left hand side expands out like so

(y-2)^2

(y-2)(y-2)

x(y-2) .... let x = y-2

xy-2x

y(x)-2(x)

y(y-2)-2(y-2) ... replace x with y-2

y^2-2y-2y+4

y^2-4y+4

So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4

--------------------------

Another approach is to pick some y value such as y = 2 to find that

(y-2)^2 = y^2-6y+4

(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2

0^2 = 2^2 - 6(2) + 4

0 = 4 - 6(2) + 4

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