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Studentka2010 [4]
3 years ago
15

What is 4/11 ÷ 7/8 equal too

Mathematics
1 answer:
galben [10]3 years ago
4 0
It equals to 32/77





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A parking garage charges $4.50 for each hour you park. You have $18 in your pocket.
Eva8 [605]

Answer:

4 hours

Step-by-step explanation:

set up your equation

money to spend = charge per hour

18 = 4.50x

divide each side by 4.50

x = 4

4 hours

3 0
3 years ago
Read 2 more answers
PLEASE HELP!!!! THANKS!!!! (WILL MARK BRAINLIEST)
Lelechka [254]

Answer:11/26=0.423076923077 so it could be .0423

Step-by-step explanation:

7 0
3 years ago
If f(x)= 3x^2- 4 and g(x) = 2x-6, what is g(f(2))?<br> -16<br> 0-2<br> O 8<br> 10
nexus9112 [7]

Answer:

10

Step-by-step explanation:

g(f(x)) = g(3x² - 4) = 2(3x² - 4) - 6

so

g(f(2) = 2(3*2² - 4) - 6 = 2*8 - 6 = 16 - 6 = 10

6 0
2 years ago
Number 5 ABC or D? Please help
RoseWind [281]

Answer:

D

Step-by-step explanation:

you want to solve it out

start with multiplying z to each. you don't multiply it to the 6 because it is in the same parenthesis set, but you multiply it to everything in the other set.  After multiplying, you get: 2z^3 , 3z^{2} , 5z

now do that to the 6. After multiplying you get:  12z^{2}, 18z, 30

now set it all next to each other 2z^3 + 3z^{2} + 5z + 12z^{2} + 18z + 30

now combine like terms. start with the to the highest power. since there is only one that has a third power, you put that one first. then you combine the squared ones, and so forth.

work combining the squares: 3z^{2} + 12z^{2} = 15z^{2}

work combing the single z's: 5z + 18z = 23z

to get this:  2z^3 + 15z^{2} + 23z + 30

so, the answer is D

4 0
3 years ago
What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*
pickupchik [31]
<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation x^4-41x^2=-400.

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

x^4-41x^2+400=-400+400.

x^4-41x^2+400=0.

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

x^4-25x^2-16x^2+400=0

Making it into two groups, we get

(x^4-25x^2)+(-16x^2+400)=0

Factoring out GCF of each group, we get

x^2(x^2-25)-16(x^2-25)=0

(x^2-25)(x^2-16) =0

Factoring out  (x^2-25) and (x^2-16) separately by difference of the squares identity a^2-b^2=(a-b)(a+b), we get

(x^2-25) = x^2-5^2= (x-5)(x+5) and

x^2-16 = x^2-4^2 =(x-4)(x+4).

Therefore,

(x-5)(x+5)(x-4)(x+4) =0

Applying zero product rule,

x-5=0

x+5=0

x-4=0 and

x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>
6 0
3 years ago
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