Step-by-step explanation:
The river is 1000 m wide, and the boat moves at 3 m/s, so the time it takes to cross the river is:
t = (1000 m) / (3 m/s)
t = 333.3 s
The river flows at 2 m/s, so by the time he reaches the other bank, he drifts downstream a distance of:
d = (2 m/s) (333.3 s)
d = 666.7 m
3y + 5.2 = 2 - 5y
3y + 5y + 5.2 = 2
8y = 2 - 5.2
8y = -3.2
y = (-3.2) / 8
y = -0.4
Answer:
note:
<em><u>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment</u></em>
Answer:
The number is 12
Step-by-step explanation:
[] First, let's turn all these words into something mathematical. N will equal "my number"
-><u> If you add 12 to my number</u> and then multiply the result by 3, you will get 64 more than two-thirds of my number.
-> n + 12 <u>and then multiply the result by 3</u>, you will get 64 more than two-thirds of my number.
-> 3(n + 12), you will get 64 more than <u>two-thirds of my number</u>.
-> 3(n + 12) = <u>64 more than</u> 
-> 3(n + 12) = 64 + 
[] Phew, okay. Now it is something we can solve and less scary;
[Given]
3(n + 12) = 64 + 
[Distribute]
3n + 36 = 64 + 
[Multiply both sides by 3]
9n + 108 = 192 + 2n
[Subtract 108 and 2n from both sides]
7n = 84
[Divide both sides by 4]
n = 12
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer: (3x + 11y)^2
Demonstration:
The polynomial is a perfect square trinomial, because:
1) √ [9x^2] = 3x
2) √121y^2] = 11y
3) 66xy = 2 *(3x)(11y)
Then it is factored as a square binomial, being the factored expression:
[ 3x + 11y]^2
Now you can verify working backwar, i.e expanding the parenthesis.
Remember that the expansion of a square binomial is:
- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2
=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.