E(1,-4) F(1,-6) G(-3,-5) H(-3,-3)
Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
First, we need the probability of picking an odd number.
There are 5 cards in total, and 3 odd cards (3, 5, and 7).
That means that the probability that we'll draw an odd card would be 
.
Then, we have 4 cards left, and 2 even cards (4 and 6), meaning that the probability that we draw an even card will be 
or 
.
To find the probability that these would happen in consecutive draws, we just multiply the probabilities together.
or 0.3.
To convert this into a percentage, we multiply the decimal by 100.
.
So the probability of picking an odd number and then picking an even number is 30%.
Hope this helps!
