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3 years ago

If x + 5 = 15 then x = 10

Mathematics

2 answers:

77julia77 [94]3 years ago

6 0

Yes u are correct x is 10

8090 [49]3 years ago

6 0

Yes x equals 10. Hope this helps

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Write an equation for the line parallel to the given line that contains <br> C(4,8);y=-3x+4

Brrunno [24]

Parallel line means they have the same slope
y = mx + b
where m = slope
y = -3 + 4
here the slope is negative 3
y = -3x + b
plug in (4, 8)
8 = -3(4) + b
b = 8 + 12
b = 20

The answer is y = -3x + 20

6 0

2 years ago

Help me class8 (surds)

Mashcka [7]

Answer:

$\cfrac{991\sqrt{2} }{80}$

Step-by-step explanation:

For a start simplify each of the roots:

$\sqrt{72} =\sqrt{36*2} =6\sqrt{2}$
$\sqrt{50} =\sqrt{25*2} =5\sqrt{2}$
$\sqrt{128} =\sqrt{64*2} =8\sqrt{2}$
$\sqrt{98} =\sqrt{49*2} =7\sqrt{2}$

Now simplify the expression in steps:

$\sqrt{72}-\cfrac{48}{\sqrt{50} } -\cfrac{45}{\sqrt{128} } +2\sqrt{98} =$

$6\sqrt{2}-\cfrac{48}{5\sqrt{2} } -\cfrac{45}{8\sqrt{2} } +2*7\sqrt{2} =$

$6\sqrt{2}-\cfrac{48*8+45*5}{5*8\sqrt{2} } +14\sqrt{2} =$

$20\sqrt{2}-\cfrac{609}{40\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609*\sqrt{2} }{40\sqrt{2} *\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{40*2 } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{80 } =$

$\sqrt{2} (20-7\cfrac{49}{80} )=$

$\sqrt{2} *12\cfrac{31}{80} =$

$\cfrac{991\sqrt{2} }{80}$

3 0

2 years ago

What is the distance of segment BF (look closely...it isn't drawn)?

Vlad [161]

The distance of BF is 7.07

4 0

2 years ago

Help me with this question plzzzz

zubka84 [21]

V = L * W * H
V = 1/4 * 2/3 * 3/5
V = (1 * 2 * 3) / (4 * 3 * 5)
V = 6/60 reduces to 1/10 m^3 <==

5 0

3 years ago

The shape above has the following

Ira Lisetskai [31]

It’s A 44-1) and if not then it’s b

8 0

2 years ago