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horrorfan [7]
2 years ago
11

Pls help me out i’ll give brainliest to best answer

Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
5 0

Answer:

5. ABC and XYZ

Step-by-step explanation:

matching angle values

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The value of the definite integral / 212x – sin(x) dx / 122x-sin(x) is
blondinia [14]

Hi there!

\boxed{= 70 + cos(12) - cos(2) \approx 71.26}

\int\limits^{12}_{2} {x-sin(x)} \, dx

We can evaluate using the power rule and trig rules:

\int x^n = \frac{x^{n+1}}{n+1}

\int x = \frac{1}{2}x^{2}

\int -sin(x) = cos(x)

Therefore:

\int\limits^{12}_{2} {x-sin(x)} \, dx = [\frac{1}{2}x^{2}+cos(x)]_{2}^{12}

Evaluate:

(\frac{1}{2}(12^{2})+cos(12)) - (\frac{1}{2}(2^2)+cos(2))\\= (72 + cos(12)) - (2 + cos(2))\\\\= 70 + cos(12) - cos(2) \approx 71.26

3 0
2 years ago
Imagine you have a classmate who has never had an introduction to statistics in a math course. Explain to that person how the pr
Tamiku [17]

Answer:

Probability of selecting red tile out of a box containing 3 red,2 white & 5 black tiles = 3/10 = 0.3

Step-by-step explanation:

Probability is the calculation of likelihood of an event.

It can be calculated by Formula : Favourable outcome / Total Outcomes

Example : If a box contain 3 red tiles, 2 white tiles, 5 black tiles

Prob (selecting a red tile) = Favourable outcome (red tiles) / Total Outcomes (total tiles) = 3 / 10 = 0.3

Similarly, prob (white tile) & prob (black tile) = 2/10 ie 0.2 & 5/10 ie 0.5 respectively

8 0
3 years ago
Identify a pair of vertical angles in the figure
Virty [35]
There are a lot of vertical angles in this figure, I will try my best to list most of them; ace,bcg bca, ecg gfd,afe gfe, dfa
6 0
2 years ago
Please Help!
vovikov84 [41]

Answer:

8

Step-by-step explanation:

We can use triangle inequality, let AC = x:

x+4 > 5

x+5 > 4

9 > x

Simplifying:

x>1

x>-1

9>x

Thus: 9>x>1

So the Largest whole number is 8

3 0
3 years ago
If two angles are supplementary, their sum equals
Black_prince [1.1K]
If two angles are supplementary, their sum equals 180 degrees
7 0
3 years ago
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