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Aleksandr-060686 [28]
3 years ago
8

Convert 11 yards to feet

Mathematics
2 answers:
gregori [183]3 years ago
5 0

Answer:

33 feet

Step-by-step explanation:

1 yard = 3 feet

11 yards = 33 feet

valkas [14]3 years ago
3 0

Answer:

33 ft

Step-by-step explanation:

We know that 3 ft = 1 yd

Multiply 11 yds by 3 ft/1 yd

11 yd * 3ft/1 yd = 33 ft

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Step-by-step explanation:

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2 years ago
What is 1/3 plus 1/6?
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The decimal is 0.0555555
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Are the 2 triangles congruent? If so, what postulate did you use?
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3 years ago
Punctele O, A, B, C sunt coliniare în această ordine, iar segmentele OA, AB și BC au lungimile exprimate în cm, prin numere natu
julia-pushkina [17]

Răspuns:

a) OC = 18cm

b) MN = 6cm

Explicație pas cu pas:

Găsiți diagrama la întrebarea atașată.

a) Din diagramă se poate observa că OC = OA + AB + AC

OC = 2n + 2n + 2 + 2n + 4

OC = 6n + 6

Următorul este să obțineți valoarea lui n:

OM = OA + AM

Să obținem segmentul AM;

Deoarece M este segmentul mijlociu al AC, atunci;

AM = AC / 2

AM = AB + BC / 2

AM = 2n + 2 + 2n + 4/2

AM = 4n + 6/2

AM = 2n + 3

Din moment ce OM = OA + AM

OM = 2n + 2n + 3

OM = 4n + 3

Dat fiind OM = 11

11 = 4n + 3

4n = 11-3

4n = 8

n = 2

Următorul pas este să calculați OC;

OC = 6n + 6

OC = 6 (2) + 6

OC = 18

Prin urmare, lungimea segmentului OC este de 18 cm

b) Această întrebare ne cere să găsim segmentul de linie MN.

Din diagramă, MN = AM - AN

Deoarece AM = 2n + 3 din întrebarea 1;

AM = 2 (2) +3

AM = 4 + 3

AM = 7

Acum, să obținem AN:

Din diagramă, AN = ON-OA și ON = OB / 2

AN = OB / 2 - OA

AN = (2n + 2n + 2) / 2 - 2n

AN = 4n + 2/2 - 2n

AN = 2n + 1 - 2n

AN = 2n-2n + 1

AN = 1

De la MN = AM - AN

MN = 7 - 1

MN = 6cm

Prin urmare, distanța dintre N, mijlocul segmentului OB și punctul M este de 6cm

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3 years ago
Davita can jog 2000 feet in 4 minutes if she jogs at the same rate how many feet can she jog in 8 minutes
slavikrds [6]
The answer is 4,000. if she can run 2,000 feet in 4 minutes, multiply both by two and the answer is 4,000 feet in 8 minutes
7 0
2 years ago
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