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77julia77 [94]
2 years ago
6

Find the zeros of the polynomial equation x⁴+2x³-13x²-14x+24=0​

Mathematics
1 answer:
STALIN [3.7K]2 years ago
4 0

Answer:×¹ = -4, ײ = -2, ׳ = 1, ×⁴ = 3

Mark me as a Brainliest

Step-by-step explanation:

Hope this helps :)

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Can someone help me lol, I need to learn this ASAP step by step
makvit [3.9K]

Answer:

Step-by-step explanation:

A. distribute the X to the X in the parenthesis and you get 2x. Then distribute the X to the -7 in the parenthesis and you get -7x. Combine like terms so that would be 2x-7x and you get -5x.

C. distribute the 6x to the X in the parenthesis and you get 7x. Then distribute the 6x to the 2 in parenthesis and you get 8x. Combine like terms so that would be 7x+8x and you get 15x.

E. Not sure on this one, sorry.

8 0
3 years ago
Delaney has $28.00 and buys a shirt for 14.00. Delaney used the equation 14x = 28 to model her scenario, where x represents the
maksim [4K]
She is incorrect because 14 multiplied by 2 equals 28, which means she wouldn’t have any money left over.
5 0
2 years ago
What is the correct answer? Please provide an explanation.
ryzh [129]

Answer:

A 270° rotation about point B'

Step-by-step explanation:

Rotation is clockwise so you can see that the final transformation is a rotation 270° clockwise

4 0
3 years ago
Read 2 more answers
Find the specified vector or scalar. . u = -4i + 1j and v = 4i + 1j; Find |u+v|. a. square root of 34. b. 5. c. 2
ExtremeBDS [4]
U = - 4 i + 1 j
v = 4 i + 1 j
| u | = √ (-4)² + 1² = √ 17
| v | = √4² + 1² = √ 17
| u + v | = √(u + v)²=
= √( u² + 2 u v + v² )= ...
cos ( u, v ) = (-16+1) / (|u| |v|) = -15/17
...= √(17 + 2 · √17 · √17 · ( -15/17) +17)  =
= √ 34 - 30 = √ 4 = 2
Answer: C ) 2 

3 0
3 years ago
If y=1/2 when x=2, find y when x=3, given that y varies directly with x
Lelu [443]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=\frac{1}{2}\\
x=2
\end{cases}\implies \cfrac{1}{2}=k2\implies \cfrac{1}{4}=k
\\\\\\
\boxed{y=\cfrac{1}{4}x}
\\\\\\
\textit{when x=3, what is \underline{y}?}\qquad y=\cfrac{1}{4}\cdot 3
4 0
3 years ago
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