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3 years ago

How do I solve this problem using the substitution method?

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

8 0

<span>(y=mx+b) or (ax+by=c) hope this helped

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"Complete the square" to convert the equation of each circle to graphing form. Identify the center and the radius.

Reil [10]

Answer:

The center is (-3,2) and the radius is r=2

Step-by-step explanation:

The general equation of the given circle is

$x^2+6x+y^2-4y=-9$

Add the square of half the coefficient of the linear terms to both sides of the equation to obtain;

$x^2+6x+3^2+y^2-4y+(-2)^2=-9+3^2+(-2)^2$

$x^2+6x+9+y^2-4y+4=-9+9+4$

$x^2+6x+9+y^2-4y+4=4$

The quadratic trinomials in x and y on the left side of the equations are perfect squares.

We factor to obtain;

$(x+3)^2+(y-2)^2=4$

$(x--3)^2+(y-2)^2=2^2$

Comparing to:

$(x-h)^2+(y-k)^2=r^2$

The center is (-3,2) and the radius is r=2

8 0

3 years ago

Helppppppppppppp pleaseeeeeeeeeeeee

satela [25.4K]

It is B because tangent lines are always perpendicular to radii

4 0

3 years ago

Read 2 more answers

Please help me , please

svp [43]

Answer:

2/3

Step-by-step explanation:

3 0

3 years ago

What is the equation of the line that passes through the point (-5,2) and has a slope of 4/5

dedylja [7]

Answer:

4x - 5y + 30 = 0

Step-by-step explanation:

When a slope of a line and a point passing through it is given then we use slope - one point form to determine the equation of the line.

It is given by:

$(y - y_1) = m (x - x_1)$

where $m$ is the slope of the line and

$(x_1, y_1)$ is the point passing through it.

Here $m = \frac{4}{5}$ and $(x_1 , y_1) = (-5,2)$ .

Substituting in the equation we get

$(y - 2) = \frac{4}{5} (x + 5)$

$\implies 5y - 10 = 4x + 20$

$\implies 4x - 5y + 30 = 0$

5 0

3 years ago

Whats the decimal equivalent of 1\4

Vesnalui [34]

The decimal equivalent of 1/4 is 0.25.

7 0

3 years ago