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3 years ago

How do I solve this problem using the substitution method?

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

8 0

<span>(y=mx+b) or (ax+by=c) hope this helped

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Given A = {a, e, i, o, u} and B = {a, l, g, e, b, r}, find A ∪ B.

harkovskaia [24]

Ahh..this is sets topics - A U B = all the elements found in A and B. But do note, do not repeat the elements if it is the same. And if the question were to ask : n(AUB) = total number of elements found in A and B.

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3 years ago

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someone please help, i don’t understand this and i’m stuck. this is my last homework i need to do for today. if you can help tha

Ad libitum [116K]

Answer:

0.38 and 0.7 maybe it's the answer

Step-by-step explanation:

power of 10 in above questions are 2 and 3 respectively

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2 years ago

The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i

Anit [1.1K]

Answer:

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The $n^{th}$ term of geometric sequence is given by:

$a_n = ar^{n-1}$

$a_4 = 16 = ar^3\\a_6 = 4 = ar^5$

Dividing the two equations, we get,

$\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}$

the first term can be calculated as:

$16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128$

Thus, the required geometric sequence is

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

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3 years ago

What is the area of triangle pqr on the grid? a triangle pqr is shown on a grid. the vertex p is on ordered pair 7 and 6, vertex

horsena [70]

P(7,6), Q(1,6), R(4,2)

We have PQ parallel to the x axis. We'll call that the base,

b = 7 - 1 = 6

The altitude is then the y difference h = 6 - 2 = 4

The area is $\frac 1 2 bh = \frac 1 2 (6)(4) = 12$

Answer: 12 square units

In general we can use the shoelace formula for the area of any polygon given coordinates. We write the points like this:

(7,6), (1,6), (4,2)

(1,6), (4,2), (7,6)

The area is then half the absolute value of the sum of the cross products:

$A = \frac 1 2 | 7(6)-6(1) + 1(2)-6(4) + 4(6)-2(7) | = \frac 1 2 |24| = 12$

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3 years ago

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The three angles of a triangle have measures of 65 degrees, 15 degrees, and (x +42) degrees. What is x?

Amiraneli [1.4K]

Answer:

58 degree is the value of x

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2 years ago