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amid [387]
3 years ago
7

Part III: Bailey works part-time at a movie theater. The theater pays employees an hourly wage based on their length of employme

nt. Write an algebraic expression that describes how much Bailey’s employer pays part-time workers.
Length of employment (months) Hourly wage (dollars/hour)
6 months                                          7.55
12 months                                        7.85
18 months                                        8.15
24 months                                        8.45
Mathematics
1 answer:
aleksklad [387]3 years ago
5 0

From the given table, the points can be written as : (6,7.55) , (12,7.85), (18, 8.15) and (24, 8.45)

Slope m=\frac{_{y2}-_{y1}}{_{x2}-_{x1}}

m = \frac{7.85-7.55}{12-6}

m = 0.05

slope intercept form of line = y=mx+c

We plug m = 0.05, x = 6 and y = 7.55 and find c.

7.55=0.05(6)+c

c= 7.25

Required equation: y=0.05x+7.25 ... Answer

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Dahasolnce [82]
The answer depends on whether you're looking for the x or the y. If y, the answers are the ones on the left, and the x on the right.

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</span><span>    +4x          +4x               -3y    -3y

     3y </span>≤ 4x + 15         -4x <span>≤ -3y + 15
</span><span>     ---     ---------          ----   ------------
      3          3               -4         -4

      y </span>≤ 4/3x + 5          x <span>≥ 3/4y + 11



2)  -6x - 4y </span>< 12         -6x - 4y < 12<span>
     +6x          +6x             +4y    +4y

     -4y </span>< 6x +12         -6x <  4y + 12<span>
     ----    ----------        ----     -----------
      -4        -4              -6          -6

        y </span>> -3/2 - 3            x > -2/3y - 2
8 0
3 years ago
Calculate the Rate of change
mylen [45]

Answer:

I think it's 0.04

Step-by-step explanation:

Each 10 years the pupil gets smaller by 0.4 millimeters

If you divide 0.4 by 10 you get 0.04 which should be millimeters per year

again dont take my word for it im not a goddess lol

5 0
3 years ago
The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q
Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

\frac{\sum f}{4}=\frac{100}{4}=25

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF)_{p} = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

     =34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75

The value of first quartile is 34.75.

Q₃ is at the position:

\frac{3\sum f}{4}=\frac{3\times100}{4}=75

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF)_{p} = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

     =44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83

The value of third quartile is 44.83.

Then the inter-quartile range is:

IQR = Q_{3}-Q_{1}

        =44.83-34.75\\=10.08

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}

                                 =\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89

Thus, the probability that a student scored at most 50 on the examination is 0.89.

5 0
3 years ago
WILL GIVE ALOT OF POINTS HELP FAST One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant
den301095 [7]

Answer:

4.4

Step-by-step explanation:

16.8 was for 4 hour

divide 4 by 16.8

you get 4.2 per hour

so you need 1 hour

1 hour would be 4.2

temp would be -4.2 at 9pm

4 0
3 years ago
Read 2 more answers
QUESTION 2<br>Simplify the following<br>a5×a7​
Kryger [21]

Answer:

a^{12}

Step-by-step explanation:

<em><u>Identity Used </u></em>:   a^x \times a^y = a^{x+ y}

   

       a^5 \times a^7 = a^{5 + 7} = a^{12}

6 0
3 years ago
Read 2 more answers
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