Total heads = 10
Total legs = 26
Cat = 4 legs
Birds = 2 legs
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Assumed all birds :
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Total legs = 10 x 2 = 20
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Difference in legs :
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26 - 20 = 6
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Difference in legs between the two animals:
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4 - 2 = 2
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Find number of cats :
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6 ÷ 2 = 3
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Find number of birds :
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10 - 3 = 7
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Answer: There are 3 cats and 7 birds.
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11,220,000,000 is the answer for this question.
8(41) + 8(5)
328 + 8(5) (multiply 8 by 41)
328 + 40 (multiply 8 by 5)
= 368 (add)
<u>Answer:</u>
<u>Step-by-step explanation:</u>
<u>We know that:</u>
<u>Work:</u>
- [{6 + (1/2 x 6)} + <u>{8 + (1/2 x 8}</u> + {BC + (1/2 x BC) = 9 + <u>s</u> + YZ
- => s = 8 + (4)
- => s = 12
Hence, <u>the value of s is 12.</u>
Hoped this helped.

Answer:
The total cost of the material was $31.35