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vivado [14]
3 years ago
11

What is 80 divided by 60

Mathematics
1 answer:
Fofino [41]3 years ago
6 0

Answer:

1.3333333333333

Step-by-step explanation:

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a sphere has a diameter of 7 centimeters what is the surface area is 3.14 to approximate Pi round to the nearest hundredth if ne
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Good idea to look up the formula for "surface area of a sphere" and to write it down for later reference.  It is A=4 pi r^2, where r is the radius of the sphere.
If the given sphere has a diameter of 7 cm, what is the radius of this sphere?

Write your answer inside the parentheses, below:

Sphere surface area = 4 pi (r)^2, or (in this case), A = 4(3.14)(        )^2
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3 years ago
Jeremy earned $33,000 after working for 44 weeks. How much money did Jeremy earn each week? Show Your Work
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Answer: jimmy needs a new job

Step-by-step explanation:

7 0
3 years ago
Joshua rolls two dice to form a two-digit
dusya [7]

Answer:

fits under statistics category (also probability or math :\)

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3 years ago
PLZZZZZZ I NEED HELP IM SO TIRED PLZZZZZZZZ
ipn [44]

Answer:

8.99

Step-by-step explanation:

\left|-46.09+51.64\right|+\left|18.08-21.52\right|

\left|-46.09+51.64\right|=5.55

\left|18.08-21.52\right|=3.44

5.55+3.44

8.99

8 0
2 years ago
LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6
USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: \mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

The coordinates are given as:

\mathbf{(x,y) = (-60,0)\ (60,0)}

The center of the hyperbola  is  

\mathbf{(h,k) = (0,0)}

The distance from the center to the focal points is given as:

\mathbf{c = 60}

Square both sides

\mathbf{c^2 = 3600}

The distance from the receiver to the transmitters  is given as:

\mathbf{2a = 100}

Divide both sides by 2

\mathbf{a = 50}

Square both sides

\mathbf{a^2 = 2500}

We have:

\mathbf{b^2 = c^2 - a^2}

This gives

\mathbf{b^2 = 3600 - 2500}

\mathbf{b^2 = 1100}  

The equation of an hyperbola is:

\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}

So, we have:

\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}

\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

Hence, the equation of the hyperbola is: \mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

Read more about hyperbolas at:

brainly.com/question/15697124

7 0
3 years ago
Read 2 more answers
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