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Elina [12.6K]
3 years ago
12

assume that the brakes in your car create a constant deceleration regardless of how fast you are going. if you double your drivi

ng speed, how does this affect (a) the time required to come to a stop, and (b) the distance needed to stop?
Physics
2 answers:
Monica [59]3 years ago
5 0
If that happens to your car and you double the speed then it will take the car longer to come to a complete stop
Novay_Z [31]3 years ago
5 0

Answer:

Part a)

Time becomes double to stop it

Part b)

Distance to stop the car will become 4 times

Explanation:

Part a)

To find the time to stop the car we know that final speed is zero

so we will have

v_f = v_i + at

here we have

0 = v - at

t = \frac{v}{a}

Now since the speed is double

so the time to stop will also becomes double

Part b)

To find the stopping distance we know that final speed of the object must be zero

so we will have

v_f^2 - v_i^2 = 2 ad

d = \frac{0 - v^2}{2(-a)}

d = \frac{v^2}{2a}

since the speed is double so the distance to stop the car will becomes 4 times

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Radda [10]
E = mc²
E = 0.235 kg · (3×10⁸ m/s)² = 0.235 · 9×10¹⁶  kg·m/s²
E = 2.115×10¹⁶ J
The answer is d) 2.12×10¹⁶ J
8 0
3 years ago
A car has a mass of 1520 kg. While traveling at 20 m⁄s, the driver applies the brakes to stop the car on a wet surface with a 0.
docker41 [41]

Answer:

(a)d₁ = 51.02 m

(b)d₂ =51.02m

Explanation:

Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration  (m/s²)

Known data

m=1520 kg  : mass of the  car

μk= 0.4 : coefficient of kinetic friction

g = 9.8 m/s² : acceleration due to gravity

Forces acting on the car

We define the x-axis in the direction parallel to the movement of the  car and the y-axis in the direction perpendicular to it.

W: Weight of the block : In vertical direction  downward

FN : Normal force :  In vertical direction  upward

f : Friction force:  In horizontal direction  

Calculated of the W

W= m*g

W=  1520 kg* 9.8 m/s² = 14896 N

Calculated of the FN

We apply the formula (1)

∑Fy = m*ay    ay = 0

FN - Wy = 0

FN = Wy

FN = 14896 N

Calculated of the f

f = μk* N= (0.4)* (14896 N )

f = 5958.4 N

We apply the formula (1) to calculated acceleration of the block:

∑Fx = m*ax  ,  ax= a  : acceleration of the block

- f = m*a

-5958.4 = (1520)*a

a  =  (-5958.4) /  ((1520)

a = -3.92 m/s²

(a) displacement of the car (d₁)

Because the car moves with uniformly accelerated movement we apply the following formula to calculate the final speed of the block :

vf²=v₀²+2*a*d₁ Formula (2)

Where:  

d:displacement  (m)

v₀: initial speed  (m/s)

vf: final speed   (m/s)

Data:

v₀ = 20 m⁄s

vf = 0

a = --3.92 m/s²

We replace data in the formula (2)  to calculate the distance along the ramp the block reaches before stopping (d₁)

vf²=v₀²+2*a*d ₁

0 = (20)²+2*(-3.92)*d ₁

2*(3.92)*d₁  = (20)²

d₁ = (20)² / (7.84)

d₁  = 51.02 m

(b)  Different car

m₂ = 1.5 *1520 kg

μk₂= 0.4

W₂= m*g

W₂=   (1.5) *1520 kg* 9.8 m/s² = (1.5)*14896 N  

FN₂=  (1.5)*14896 N  

f= 0.4* (1.5)*14896 N  

a = - f/m₂ = - 0.4* (1.5)*14896 N  /(1.5) *1520

a = -3.92   m/s²

vf²=v₀²+2*a*d₂

vf=0 , v₀=20 m⁄s , a = -3.92   m/s²

d₂ = d₁ = 51.02m

6 0
4 years ago
In which of these media will mechanical waves travel the slowest in?
Aleks [24]

Answer:

E

Explanation:

it has more mass

5 0
3 years ago
what is formed when two or more substances are so evenly mixed that you can't see the different parts
Andre45 [30]
A homogenous mixture
5 0
4 years ago
Waves travel along a 100-m length of string which has a mass of 55 g and is held taut with a tension of 75 N. What is the speed
Dvinal [7]

Answer:

v=369.27\frac{m}{s}

Explanation:

The speed of the waves in a string is related with the tension and mass per unit length of the string, as follows:

v=\sqrt\frac{T}{\mu}

First, we calculate the mass per unit length:

\mu=\frac{m}{L}\\\mu=\frac{55*10^{-3}kg}{100m}\\\mu=5.5*10^{-4}\frac{kg}{m}

Now, we calculate the speed of the waves:

v=\sqrt\frac{75N}{5.5*10^{-4}\frac{kg}{m}}\\v=369.27\frac{m}{s}

8 0
4 years ago
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