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2 years ago

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A cord of mass 0.65 kg is stretched between two supports 8.0 m apart. If the tension in the cord is 120 N, how long will it take

a pulse to travel from one support to the other

1 answer:

DedPeter [7]2 years ago

7 0

The time taken by the pulse to travel from one support to the other is 0.208 s.

<h3>Given:</h3>

The mass of the cord is m = 0.65 kg.

The distance between the supports is, d = 8.0 m.

The tension in the cord is T = 120 N.

The time taken by the pulse to travel from one support to the other is given as,

$v=\frac{d}{t}$

$t=\frac{d}{v}$

Here, v is the linear velocity of a pulse. Its value is,

$v=\sqrt{\frac{T d }{m} }$

$v=\sqrt{\frac{120 * 8}{0.65} }$

$v= 38.43 m/s$

Then,

$t=\frac{8}{38.43}$

$t=0.208 s$

Thus, the time taken by the pulse to travel from one support to the other is 0.208 s.

Learn more about tension here:

brainly.com/question/24994188

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Write an expression for the magnitude of charge moved, Q, in terms of N and the fundamental charge e

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From the question we are told

Write an expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e

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