Answer:

Explanation:
Given that,
Initial speed, u = 0
Final speed, v = 40 m/s
Time, t = 2 s
We need to find the acceleration of the aircraft. We know that, acceleration is equal to the rate of change of velocity. So,

So, the acceleration of the aircraft is
.
Sound travels fastest in solids. A sound is a vibration that travels in a longitudinal direction through a medium in the form of a mechanical wave.
<h3>What is sound?</h3>
A sound is a vibration that travels in a longitudinal direction through a medium in the form of a mechanical wave.
It can propagate through a solid, a liquid, or a gas as its medium. Solids go the fastest, liquids are slower, and gases are the slowest.
Sound travels the quickest through a solid because the molecules are packed together densely, allowing sound waves to leap from one molecule to the next more quickly.
Because the molecules in solids are packed the tightest, sound travels the quickest through them, whereas sound travels the slowest through gases.
To learn more about the sound refer to the link;
brainly.com/question/927975
<span> Maths delivers! Braking distance ... If the </span>car<span> is initially travelling at u</span>m<span>/s, then the stopping distance d </span>m<span> ... the </span>speed<span> of the </span>car<span> at the </span>instant<span> the </span>brakes<span> are applied. ... An object with </span>constant acceleration<span> travels the </span>same<span> distance as it would ... We </span>start<span> with the second equation of motion:.</span>
Answer:
The force per unit length (N/m) on the top wire is 16.842 N/m
Explanation:
Given;
distance between the two parallel wire, d = 38 cm = 0.38 m
current in the first wire, I₁ = 4.0 kA
current in the second wire, I₂ = 8.0 kA
Force per unit length, between two parallel wires is given as;

where;
μ₀ is constant = 4π x 10⁻⁷ T.m/A
Substitute the given values in the above equation and calculate the force per unit length

Therefore, the force per unit length (N/m) on the top wire is 16.842 N/m