If your speedometer has an uncertainty of 2.5 km/h at a speed of 92 km/h, what is the percent uncertainty
1 answer:
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A) when the spring is released, all the elastic potential energy of the spring is converted into kinetic energy of the mass in motion. So we can write:
where
is the elastic constant of the spring, 
is its displacement, 
is the mass of the block and 
the velocity of the block after it is released from the spring. So we can find v:
This is the velocity the block has before entering the rough path bc.
b) After it enters the rough path, the block starts to lose energy because of the work
done by the frictional force with frictional coefficient of 
. So, calling Kf and Ki the final and initial kinetic energy, we have
the length of the rough path bc is 20 cm=0.2 m, so the work done by the frictional force is
while the initial kinetic energy is
Therefore kinetic energy after the rough path is
and the velocity is
c)
found at point b) is the kinetic energy of the block before entering the incline. At the maximum height h, all this kinetic energy is converted into potential energy, mgh. So we can write
and from this we find h:
where
This is the velocity the block has before entering the rough path bc.
b) After it enters the rough path, the block starts to lose energy because of the work
the length of the rough path bc is 20 cm=0.2 m, so the work done by the frictional force is
while the initial kinetic energy is
Therefore kinetic energy after the rough path is
and the velocity is
c)
and from this we find h: