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LekaFEV [45]
2 years ago
14

Find the number for which: 75% is 4.5 cm

Mathematics
1 answer:
Aneli [31]2 years ago
3 0
4.5/3= 1.5*4

6 is your answer
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Please help I will reward brainly
krok68 [10]
Hi there!

Since the sum of all angles in any triangle always adds up to 180 degrees, we can calculate this and solve for x.

4x + x + x = 180°
6x = 180
180 ÷ 6 = x
x = 30

So, now we know that x is 30°.

Hope this helps!
7 0
3 years ago
Shelly wants to have 6 rose bushes planted on her property. She asked a landscaping company to give her a bid. The contractor wa
Anton [14]

Answer:

$360

Step-by-step explanation:

If Shelly wants 6 rose bushes, and each bush costs $40, then you can multiply 6 by 40 to find the total amount of money Shelly will spend on them if she plants them herself. 6 x 40 = 240. You can then subtract 240 from 600 to find the amount of money she saves. 600 - 240 = 360

3 0
2 years ago
Read 2 more answers
PLEASE HELP> I NEED ANSWER ASAP. GEOMETRY
OlgaM077 [116]

Answer:

Angle 4=82 degrees, then i think angle 1 and 3= 98 degrees

Step-by-step explanation:

Angle 2=Angle 4 and 180-82=98

6 0
2 years ago
The length of a rectangle is 5 in longer than its width. if the perimeter of the rectangle is 34 in , find its area.
shtirl [24]
Area(A)= lw
perimeter(P)= 2w+2l= 34in
length(l)= w+5 
width(w)= w

1/2 P= 17= w+l
17= w+(w+5)
17= 2w+5
2w=12
w=6 in

l= w+5
l= 6+5
l=11 in


A= lw= (11)(6)= 66in²

Answer:
Area of rectangle is 66 in².
3 0
3 years ago
4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513
dimaraw [331]

Answer:

Part 4) sin(\theta)=\frac{12}{13}

Part 10) The angle of elevation is 40.36\°

Part 11) The angle of depression is 78.61\°

Part 12) arcsin(0.5)=30\°  or arcsin(0.5)=150\°

Part 13) -45\°  or 225\°

Step-by-step explanation:

Part 4) we have that

cos(\theta)=-\frac{5}{13}

The angle theta lies in Quadrant II

so

The sine of angle theta is positive

Remember that

sin^{2}(\theta)+ cos^{2}(\theta)=1

substitute the given value

sin^{2}(\theta)+(-\frac{5}{13})^{2}=1

sin^{2}(\theta)+(\frac{25}{169})=1

sin^{2}(\theta)=1-(\frac{25}{169})  

sin^{2}(\theta)=(\frac{144}{169})

sin(\theta)=\frac{12}{13}

Part 10)

Let

\theta ----> angle of elevation

we know that

tan(\theta)=\frac{85}{100} ----> opposite side angle theta divided by adjacent side angle theta

\theta=arctan(\frac{85}{100})=40.36\°

Part 11)

Let

\theta ----> angle of depression

we know that

sin(\theta)=\frac{5,389-2,405}{3,044} ----> opposite side angle theta divided by hypotenuse

sin(\theta)=\frac{2,984}{3,044}

\theta=arcsin(\frac{2,984}{3,044})=78.61\°

Part 12) What is the exact value of arcsin(0.5)?

Remember that

sin(30\°)=0.5

therefore

arcsin(0.5) -----> has two solutions

arcsin(0.5)=30\° ----> I Quadrant

or

arcsin(0.5)=180\°-30\°=150\° ----> II Quadrant

Part 13) What is the exact value of arcsin(-\frac{\sqrt{2}}{2})

The sine is negative

so

The angle lies in Quadrant III or Quadrant IV

Remember that

sin(45\°)=\frac{\sqrt{2}}{2}

therefore

arcsin(-\frac{\sqrt{2}}{2}) ----> has two solutions

arcsin(-\frac{\sqrt{2}}{2})=-45\° ----> IV Quadrant

or

arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\° ----> III Quadrant

5 0
3 years ago
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