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Anton [14]
3 years ago
12

Please help me with question 19

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
8 0

Alright, lets get started.

Suppose the smaller integer = n

So, larger integer will be = n+2

3 times of larger integer will be = 3(n+2)

smaller integer is added into this , so

n +3 (n+2)

The result is 2 less than 5 times of smaller integer, so

5n - 2

Both are equal so,

n + 3 (n+2) = 5n - 2

n + 3n + 6 = 5n - 2

Rafael makde the mistake that he didn't put the larger integer into parenthesis like (n+2) , so three times will be 3 n + 6 as he got 3n + 2

So, the correct equation is

n +3n +6 = 5n - 2

Solving the equation

4n + 6 = 5n - 2

n = 8

So, saller integer is 8 and larger integer is 8 + 2 = 10

So, both integers are 8 and 10.  :  Answer

Hope it will help :)


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Bingel [31]
Simplify the exponents
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Suppose h(x)=3x-2 and j(x) = ax +b. Find a relationship between a and b such that h(j(x)) = j(h(x))
sergejj [24]

Answer:

\displaystyle a = \frac{1}{3} \text{ and } b = \frac{2}{3}

Step-by-step explanation:

We can use the definition of inverse functions. Recall that if two functions, <em>f</em> and <em>g</em> are inverses, then:

\displaystyle f(g(x)) = g(f(x)) = x

So, we can let <em>j</em> be the inverse function of <em>h</em>.

Function <em>h</em> is given by:

\displaystyle h(x) = y = 3x-2

Find its inverse. Flip variables:

x = 3y - 2

Solve for <em>y. </em>Add:

\displaystyle x + 2 = 3y

Hence:

\displaystyle h^{-1}(x) = j(x) = \frac{x+2}{3} = \frac{1}{3} x + \frac{2}{3}

Therefore, <em>a</em> = 1/3 and <em>b</em> = 2/3.

We can verify our solution:

\displaystyle \begin{aligned} h(j(x)) &= h\left( \frac{1}{3} x + \frac{2}{3}\right) \\ \\ &= 3\left(\frac{1}{3}x + \frac{2}{3}\right) -2 \\ \\ &= (x + 2) -2 \\ \\ &= x \end{aligned}

And:

\displaystyle \begin{aligned} j(h(x)) &= j\left(3x-2\right) \\ \\ &= \frac{1}{3}\left( 3x-2\right)+\frac{2}{3} \\ \\ &=\left( x- \frac{2}{3}\right) + \frac{2}{3} \\ \\ &= x  \stackrel{\checkmark}{=} x\end{aligned}

3 0
3 years ago
What is the 214 term in the sequence 7,10,13,16?
mixer [17]
We can figure this out using the explicit formula.

f(n)=f(1)+d(n-1)

n represents the term we are looking for.
f(1) represents the first term in the sequence, which in this case, is 7.
d represents the common difference, which in this case, is +3.

f(n) = 7 + 3(n - 1)
f(n) = 7 + 3n - 3
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Now, we can input 214 for n and solve.

f(214) = 4 + 3(214)
f(214) = 4 + 642
f(214) = 646

The 214th term in this sequence is 646.
5 0
4 years ago
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