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3 years ago

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Two systems of equations are shown below:

2 answers:

Sati [7]3 years ago

6 0

System A:
6x + y = 2
-x - y = -3

System B:
2x - 3y = -10
-x-y = -3

Solve:
System A:
6x + y = 2
y = 2 - 6x
-x - (2-6x) = -3
-x - 2 + 6x = -3
5x = -3 + 2
5x = -1
x = -1/5
y = 2 - 6(-1/5)
y = 2 + 6/5
y = 2 + 1.2
y = 3.2 System A: x = -1/5 or -0.2 ; y = 3 1/5 or 3.2

System B:
2x - 3y = -10
2x = -10 + 3y
x = -5 + 1.5y
-x - y = -3
-(-5 + 1.5y) -y = -3
5 - 1.5y - y = -3
-2.5y = -3 - 5
-2.5y = -8
y = 3.2
x = -5 + 1.5(3.2)
x = -5 + 4.8
x = -0.2 System B: x = -0.2 ; y = 3.2

<span>B) They will have the same solution because the first equations of both the systems have the same graph.</span>

Alchen [17]3 years ago

6 0

Answer: I just took the test and got it wrong when I put B, the correct answer is C.

Step-by-step explanation:

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The midpoint of GH is M( 6,-4). One endpoint is G(8,-2). Find the coordinates of endpoint H.

Finger [1]

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<h3>The Midpoint Formula</h3>

The midpoint formula is given as: $(x_m, y_m) = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} )$

<em>Where</em>,

$(x_m, y_m)$ = coordinates of the midpoint

$(x_1, y_1)$ = coordinates of the first point

$(x_2, y_2)$ = coordinates of the second point

Given the following:

$(x_m, y_m)$ = M( 6,-4)

$(x_1, y_1)$ = G(8,-2)

$(x_2, y_2)$ = H(?, ?)

Plug in the values into the midpoint formula

$M(6, -4) = (\frac{8 + x_2}{2}, \frac{-2 + y_2}{2} )$

Solve for the x-coordinate and y-coordinate separately

$6 = \frac{8 + x_2}{2}$

Multiply both sides

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$-4 = \frac{-2 + y_2}{2}\\\\-8 = -2 + y_2\\\\-8 + 2 = y_2\\\\-6 = y_2\\\\\mathbf{y_2 = -6}$

Therefore, using the midpoint formula, the coordinates of endpoint H are (4, -6).

Learn more about midpoint formula on:

brainly.com/question/13115533

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