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3 years ago

Which statement does not describe the cosine function?

Mathematics

2 answers:

Lady bird [3.3K]3 years ago

7 0

Answer: The correct answer is: The cycle repeats every 2π radians.

Step-by-step explanation:

Ap3x Approved

aleksley [76]3 years ago

7 0

Answer:

B: Its range includes all real numbers

Step-by-step explanation:

Ap3x says soB B)

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A system of equations that has at least one solution is called inconsistent.

solmaris [256]

False. Because if it has one then it is consistent.

Source: If a consistent system has an infinite number of solutions, it is dependent . When you graph the equations, both equations represent the same line. If a system has no solution, it is said to be inconsistent. (https://www.varsitytutors.com/hotmath/hotmath.../consistent-and-dependent-systems)

8 0

3 years ago

Read 2 more answers

Select all operations under which the polynomials 5x - 1 and 3x - 10 are not closed.

sammy [17]

It's division.
Hope I helped!

7 0

3 years ago

What is the least common denominator for 2-3,4-5,1-2

Masja [62]

2-3=1
4-5=20
1-2=1
i think this is it i have never really been good at this but i think it could be those one

8 0

3 years ago

A rectangular bedroom is 2 ft longer than it is wide. It's area is 288 ft2. What is the width of the room?

Ulleksa [173]

Answer:

96ft

Step-by-step explanation:

length=x+2

width=x

x+2*x=288

3x=288

x=96

4 0

3 years ago

Read 2 more answers

A given field mouse population satisfies the differential equation dp dt = 0.5p − 410 where p is the number of mice and t is the

ohaa [14]

Answer:

a) $t = 2 *ln(\frac{82}{5}) =5.595$

b) $t = 2 *ln(-\frac{820}{p_0 -820})$

c) $p_0 = 820-\frac{820}{e^6}$

Step-by-step explanation:

For this case we have the following differential equation:

$\frac{dp}{dt}=\frac{1}{2} (p-820)$

And if we rewrite the expression we got:

$\frac{dp}{p-820}= \frac{1}{2} dt$

If we integrate both sides we have:

$ln|P-820|= \frac{1}{2}t +c$

Using exponential on both sides we got:

$P= 820 + P_o e^{1/2t}$

Part a

For this case we know that p(0) = 770 so we have this:

$770 = 820 + P_o e^0$

$P_o = -50$

So then our model would be given by:

$P(t) = -50e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=-50 e^{1/2 t} +820$

$\frac{820}{50} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(\frac{82}{5}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(\frac{82}{5}) =5.595$

Part b

For this case we know that p(0) = p0 so we have this:

$p_0 = 820 + P_o e^0$

$P_o = p_0 -820$

So then our model would be given by:

$P(t) = (p_o -820)e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=(p_o -820)e^{1/2 t} +820$

$-\frac{820}{p_0 -820} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(-\frac{820}{p_0 -820}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(-\frac{820}{p_0 -820})$

Part c

For this case we want to find the initial population if we know that the population become extinct in 1 year = 12 months. Using the equation founded on part b we got:

$12 = 2 *ln(\frac{820}{820-p_0})$

$6 = ln (\frac{820}{820-p_0})$

Using exponentials we got:

$e^6 = \frac{820}{820-p_0}$

$(820-p_0) e^6 = 820$

$820-p_0 = \frac{820}{e^6}$

$p_0 = 820-\frac{820}{e^6}$

8 0

3 years ago