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3 years ago

I NEED HELP!!!

Mathematics

1 answer:

DENIUS [597]3 years ago

7 0

2/3 of a box per 30 secs

2/3 times 2 = 4/3 = 1 1/3

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Eli is driving on a long road trip. He currently has 12 gallons of gas in his car. Each

AlladinOne [14]

Answer:

I would be 7 gallons used and 5 gallons left

Step-by-step explanation:

multyply 1.75 times 4 hours equal 7 then 12-7=5 is the total of gallons left

Hope this helps

5 0

3 years ago

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Use the function f(x) and g(x); to answer the question. f(x)=x^2+10;g(x)=x-3. which expression is equal to (f+g)(x)?

Ket [755]

Answer:

X'2+x+7 (Option c

Step-by-step explanation:

Check attachment

7 0

3 years ago

Rewrite the equation 5x - 2y = 4 so it is in the form y = mx + b

muminat

Y=(5x-4)/2 first move -2y to the other side to obtain a positive value and make y the subject

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3 years ago

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NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

3 0

2 years ago

Use the given triangles to evaluate the expression. Rationalize all denominators. <br> cos Pi/6

Rainbow [258]

There is no figure of the triangle, all that I know about it is
<span>cos Pi/6 =√3/2</span>

7 0

3 years ago