Write and solve an inequality, You want to save at least $100. How much do you need to save if you start with $37?

A ladder 13 feet long is leaning against a house. The base of the ladder is pulled away from the wall at a rate of 2 feet per s

Kamila [148]

I believe the answer is 10 feet per second?

4 0

2 years ago

10 kilograms =?grams

max2010maxim [7]

10 kilograms is equal to 10,000 grams

Step-by-step explanation:

1 kilogram = 1000 grams

To know how many grams does 10 kilograms consists is we need to multiply with 1000 to 10 then we can obtain 10 kilograms in grams.

10 kilograms = 10 × 1000

10 kilograms = 10,000 grams.

"Kilogram" is the unit of "mass". The standard unit of "mass" in the "International system" of units the "mass" is represented by "Kilogram".

The symbol for "Kilogram" is "Kg".

8 0

3 years ago

Does going to a private university increase the chance that a student will graduate with student loan debt? A national poll by t

Snowcat [4.5K]

Answer:

Null hypothesis: $p \leq 0.69$

Alternative hypothesis: $p > 0.69$

Step-by-step explanation:

1) Data given and notation

n=1500 represent the random sample taken

X represent the number of graduates that had student loan debt in 2014

$\hat p=0.71$ estimated proportion of adults that said that it is morally wrong to not report all income on tax returns

$p_o=0.69$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that if there was a significant increase in the proportion of student loan debt for public and nonprofit colleges in 2014 respect to the value of 2013.:

Null hypothesis: $p \leq 0.69$

Alternative hypothesis: $p > 0.69$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.71 -0.69}{\sqrt{\frac{0.69(1-0.69)}{1500}}}=1.675$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>1.675)=0.047$

If we compare the p value obtained and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults that said that it is morally wrong to not report all income on tax returns is not significantly higher than 0.69.