Answer: x=1,y=0
Step-by-step explanation:
X-2y=1.....equation 1
2x-y=2.....equation 2
X=1+2y.......equation 3
Substitute equation 3into 2
2(1+2y)-y=2
2+4y-y=2
2+3y=2
3y=2-2
3y=0
Y=0/3
Y=0
Substitute for y=0 in equation 1
X-2y=1
X-2(0)=1
X-0=1
X=1
X=1 & Y=0
Answer:
(2,-3)
Step-by-step explanation:
I thought you'd actually have to calculate it but I guess they just wanted to give you guys a graph lol
3x=x+40
Subtract x from both sides
2x=40
Divide both sides by 2nto get x by itself
x=2
Plug 2 in for x
m∠4 = (3x)
m∠4 = 3(2)
Solve
m∠4 = 6
N = the number
9/10n + 6 = 51 Original Problem.
9/10n = 46 Subtract 6 from each side.
n = 51.11111111111111111111 Multiply each side by (10/9)
Answer: n = 51.111111111111111111111
A three-dimensional vector field is conservative if it is also irrotational, i.e. its curl is

. We have

so this vector field is not conservative.
- - -
Another way of determining the same result: We want to find a scalar function

such that its gradient is equal to the given vector field,

:

For this to happen, we need to satisfy

From the first equation, integrating with respect to

yields

Note that

*must* be a function of

only.
Now differentiate with respect to

and we have

but this contradicts the assumption that

is independent of

. So, the scalar potential function does not exist, and therefore the vector field is not conservative.