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3 years ago

What is the quotient of (x3 + 6x2 + 11x + 6) ÷ (x2 + 4x + 3)? x + 2 x – 2 x + 10 x + 6

Mathematics

1 answer:

evablogger [386]3 years ago

6 0

Answer:

x + 2

Step-by-step explanation:

If we know one of the factors, we should be able to use long division.

We can divide the trinomial by the binomial and find the other factor.

x + 2

x² + 4x + 3)x³ + 6x² + 11x + 6

x³ + 4x² + 3x

2x² + 8x + 6

2x² + 8x + 6

Thus,

$\dfrac{x^{3} + 6x^2 + 11x + 6} {x^{2} + 4x + 3} = \mathbf{x + 2}$

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nirvana33 [79]

The number is 14. You can put it in an equation by writing 14 + (14 ÷ 2) = 21

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Write 2/4 in lowest terms

ycow [4]

Answer:

1/2

Step-by-step explanation:

Divide it by 2 on both sides. 2/2 is 1. 4/2 is 2. So 1/2

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2 years ago

ASAP! Question 3: The following data give the weights (in pounds) lost by 15 members of a health club at the end of 2 months aft

Klio2033 [76]

Answer:

First arrange the data in an order

3, 3, 3, 7, 7, 10, 10, 12, 12, 13, 14, 17, 17, 18, 21

a.) Q1 = (N + 1)/4th item = (15 + 1)/4 = 4th item = 7

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Q3 = 3(16)/4 = 3(4) = 12th item = 17

IQR = (Q3 - Q1)/2 = (17 - 7)/2 = 10/2 = 5

b.) 82nd percentile = 82(16)/100 = 13th item = 17

c.) 12 is the 8th item which is in the middle of the data set, so the percentile rank is 50%

Step-by-step explanation:

3 0

3 years ago

Which answer is correct? It wouldn’t let me click mathematics btw

Bad White [126]

6)
KM bisects on <NKL so m<MKN = m<MKL = 3x + 5

2(m<MKL) + m<JKN = 180
2(3x+5) + 8x + 2 = 180
6x + 10 + 8x + 2 = 180
14x + 12 = 180
14x = 168
x = 12

so
m<MKN = m<MKL = 3x + 5 = 3(12) + 5 = 36 + 5 = 41

answer
b. 41

7)

2 supplementary has sum = 180
x + x + 14 = 180
2x + 14 = 180
2x = 166
x = 83
x + 14 = 83 + 14 = 97

2 angles are 83 and 97

answer
b. 83, 97

7 0

3 years ago

The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.

pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

$m_{1}\times m_{2}=-1$

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

$m_{normal} \times m_{tangent}=-1$

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

$m=\frac{y_2-y_1}{x_2-x_1}$

$=\frac{8-4}{-6+6}$

= ∞

Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0

Hence m=0

Putting m=0 in equation 1 we get:

c = 8

The equation of tangent line at (-6,8) is:

y = 8

6 0

3 years ago