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3 years ago

CIU-ZUJURVATEU

Mathematics

2 answers:

MrRa [10]3 years ago

6 0

Median = 98 : 93,96,98,101,104

Median = 103 : 101, 108....

Median = 105 : 98, 100...

Step-by-step explanation: sorry I was lazy and didn’t feel like writing all the # down. those are the first few # In each answer answer so..‍♀️

Dafna11 [192]3 years ago

3 0

Answer:

First one = Median 103

Second one = Median 105

Third one = Median 98

Step-by-step explanation:

I got it correct, Edge2020!

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Boris choos three diffrent numbers.the sum of the three numbers is 36.One of trh numbers is a cube number.the other two number a

inna [77]

Answer:

4,5,27

Problem:

Boris chose three different numbers.

The sum of the three numbers is 36.

One of the numbers is a perfect cube.

The other two numbers are factors of 20.

Step-by-step explanation:

Let's pretend those numbers are:

$a,b, \text{ and } c$ .

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One of our numbers is a perfect cube. $a=n^3$ where $n$ is an integer.

The other two numbers are factors of 20. $bk=20$ and $ci=20$ where $a,c,i, \text{ and } k \text{ are integers}$ .

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From here I would just try to find numbers that satisfy the conditions using trial and error.

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3 years ago

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Answer:

The answer is

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Step-by-step explanation:

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