Ask question

Ask question

All categories

2 years ago

10

Follow nikespear37 tik tok

2 answers:

nekit [7.7K]2 years ago

6 0

I dont know what your talking about

hjlf2 years ago

4 0

Answer:

no >:)

Step-by-step explanation:

You might be interested in

Find the inverse of f(x)= -x + 3

inna [77]

Let g the inverse function of f.

The most important property of g and f being inverses of each other, is that

g(f(x))=x, also f(g(x))=x

so, what one function 'does' to x, the other 'undoes' it.

Thus, we have:

f(g(x))=x and alos f(g(x))= -g(x)+3, from the rule

thus :

-g(x)+3=x

-g(x)=x-3

g(x)=-x+3

check: f(g(x))=f(-x+3)=-(-x+3)+3=x-3+3=x

Answer: the inverse of f is g, such that g(x)=-x+3

4 0

2 years ago

2x+2x-26=114 blank -26=114

Nady [450]

The answer is 35

X= 35

3 0

2 years ago

A pound of chocolate costs 8 dollars. Ann buys p pounds. Write an equation to represent the total cost c that Ann pay

aleksandrvk [35]

Answer:

Since it is 6 dollars per pound, his total cost c is 6 times p...thus

c = 6p

Hope this helps and hopefully I can get brainliest.

5 0

3 years ago

Find the value of n<br><br> 3n-10<br> n=

Mars2501 [29]

10-3=N

N=7

Step-by-step explanation:

hope you like it

8 0

2 years ago

Read 2 more answers

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

$114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)$

Applying the following property of exponentials numbers in (II):

$e^{a}.e^{b}=e^{a+b}$

Therefore $e^{-28k}$ can be written as $e^{-14k}.e^{-14k}$

$152=190-Ae^{-14k}.e^{14k}$

Replacing (I) in the previous equation:

$152=190-76e^{-14k}$

Solving for k:

Subtracting 190 both sides, dividing by -76:

$0.5=e^{-14k}$

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

$Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76$

Dividing by 0.5

A=152

7 0

2 years ago