First we need to find the common ratio by dividing the second term by the first term. 36/120 = 3/10
an = a1 * r^(n-1)
n = term to find = 5
a1 = first term = 120
r = common ratio = 3/10
now we sub and solve
a5 = 120 * 3/10^(5 - 1)
a5 = 120 * 3/10^4
a5 = 120 * .0081
a5 = 0.972 <=== fifth term
or we could have just done this......since we multiply by 3/10 to find the next number...
a3 = 10.8......10.8 * 3/10 = 3.24 <== 4th term
3.24 * 3/10 = 0.972 <== fifth term
It would be pounds, hope this helps :)
Get it in form 4P(y-k)=(x-h)^2
add 8y to both sides
x^2-6x+49=8y
complete the square
-6/3=-3, (-3)^2=9
(x^2-6x+9)+40=8y
(x-3)^2+40=8y
minus 40 both sides
(x-3)^2=8y-40
undistribute 8 on right side
(x-3)^2=(y-5)8
4P(y-k)=(x-h)^2
4(2)(y-5)=(x-3)^2
(h,k) is center
p is distance from vertex to directix and also from vertex to focus
p=2
vertex=(3,5)
in that form, the prabola opens up so
directix is 2 below vertex
focus is 2 above vertex
up and down is y so
5-2=3
5+2=7
directix is y=3
focus=(3,7)
vertex=(3,5)
