Answer:
∠J = 60°
Step-by-step explanation:
The Law of Cosines tells you ...
j² = k² +l² -2kl·cos(J)
Solving for J gives ...
J = arccos((k² +l² -j²)/(2kl))
J = arccos((14² +80² -74²)/(2·14·80)) = arccos(1120/2240) = arccos(1/2)
J = 60°
_____
<em>Additional comment</em>
It is pretty rare to find a set of integer side lengths that result in one of the angles of the triangle being a rational number of degrees.
The trinomial that results from foiling the binomials is 6x^2+41x+30.
It’s 4/15
Answer = 3 3/4
I hope that helps :)
Answer:
The GCF for the numerical part is 2
Step-by-step explanation:
6x^2y^2-8xy^2+10xy
It contains both numbers and variables, there are two steps to find the GCF(HCF).
1). Find the GCF for the numerical part 6, -8,10
2). Find the GCF for the variable part x^2,y^2,x^1,y^2,x^1,y^3
3).Multiply the values together.
Find the common factors for the numerical part:
6,-8,10
Factors of 6
6: 1,2,3,6
Factors of -8
-8: -8,-4,-2,-1,1,2,4,8
Factors of 10
10:1,2,5,10
Common factors of 6,-8, 10 are 1,2
The GCF Numerical=2
The GCF Variable= xy^2
Multiply the GCF of the numerical part 2 and the GCF of the variable part xy^2, and you'll get 2xy^2
Answer:
552
Step-by-step explanation:
This is a problem of permutation which can be solved by rule of fundamental counting principle.
This principle states that if there "m" ways of doing one thing and "n" ways of doing other. Then no. of ways in which both the things can be done together is "m*n". This can be extended for m, n, p,r, s things and so on.
example: if there are 5 shirts and 3 trousers then number of ways in which the shirts and trousers can be worn is 5*3 = 15 ways.
_____________________________________________
The given problem is on similar concepts.
here 6 short stories, 4 novels, and 23 poems have to be assigned to his class.
Thus it can be done in 6*4*23 = 552 ways.
