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2 years ago

21-3+18÷6=6 Determine if True?

Mathematics

2 answers:

Lunna [17]2 years ago

7 0

Answer:

False

Step-by-step explanation:

$21-3+18\div 6 \\\\=21-3+3\\\\=21-0\\\\=21\neq 6$

Pavel [41]2 years ago

6 0

Answer:

False

Step-by-step explanation:

Consider left side

21 - 3 + 18 ÷ 6

Following the rules of PEMDAS

division is performed before addition/ subtraction

= 21 - 3 + 3

= 21 + 0

= 21 ≠ 6

thus the initial statement is False

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Free_Kalibri [48]

Answer:

1.(1,5) and (2,6) , 6-5/2-1=1/1 m=1 ,y=1x+b

5=1(1)+b 4=b

y=x+4

2.(1,1) and (3,-8) -8-1/3-1=-9/2 m=-9/2 ,y=-9/2x+b

1=-9/2(1)+b b=11/2

y=-9/x+11/2

3.(2.-3) and (5,-2) m=1/3 ,y=1/3x+b

-3=1/3(2)+b -3=2/3+b

-3-2/3=b

b=-11/3

y=1/3x-11/3

4.(2,5)and (4,3) m=-1 y=-1x+b

5=-1(2)+b 5=-2+b

5+2=b

b=7

y=-1x+7

6.(-3,-5) and (-1,-3) m=2/2=1 y=1x+b

-5=1(-3)+b -5=-3+b

-5+3=b

-2=b

y=1x-2

Step-by-step explanation:

7 0

3 years ago

WILL GIVE BRAINLIEST! Find k so that (5, k) is equidistant from (–1, 2) and (3, 0).

pochemuha

Answer:

Step-by-step explanation:

So first I created 2 distance forumlas and set them equal to each other

$\sqrt{(5+1)^2+(k-2)^2} =\sqrt{(5-3)^2+(k)^2}$

then I simplified them

$(5+1)^2+(k-2)^2 =(5-3)^2+(k)^2\\$

$36 + k^2 - 4k +4 = k^2 + 4$

$-4k + 36 = 0\\$

$4k = 36$

$k = 9$

when k = 9, the two distances are equal

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4 years ago

I already made an attempt at this question and I would just like to check my answer z = ?

Salsk061 [2.6K]

So we have the equation:

$\frac{z+9}{4}=2.1$

Then we need to multiply by 4 on both sides to get rid of the denominator on the left:

$z+9=8.4$

Then we subtract 9 on both sides to solve for z:

$z=-0.6$

Therefore the answer is z = -0.6.

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