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3 years ago

9

A rectangle on a coordinate plane has vertices Q(Negative 1, 1), R(6, 1), S(6, Negative 8), and T(Negative 1, Negative 8). What

are the dimensions of the rectangle?

1 answer:

Reptile [31]3 years ago

3 0

Answer:

there is no picture

Step-by-step explanation:

i need to see a picture to answer this :(

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2/5=6/15
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yes. that would be the last one possible.

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Given: N is the midpoint of LQ,

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Answer:

6. SAS Postulate

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Step-by-step explanation:

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2 years ago

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Can someone help me how to solve this?

Assoli18 [71]

Answer:

x > -5 in the answer

Step-by-step explanation:

(5 - 3x) / 4 < 5

multiplying both sides by 4:-

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3 years ago

The 13th term of a geometric sequence is 16, 384 and the first term is 4. What is the common ratio?

AleksAgata [21]

Answer:

$\large \boxed{2}$

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

aₙ = a₁rⁿ⁻¹

In your geometric sequence, a₁ = 4 and a₁₃ = 16 384.

$\begin{array}{rcl}16384 & = & 4r^{(13 - 1)}}\\16384 & = & 4r^{12}\\4096 & = & r^{12}\\3.6124 & = & 12 \log r\\0.30102 & = & \log r\\r & = & 10^{0.30102}\\ & = & \mathbf{2}\\\end{array}\\\text{The common ratio is $\large \boxed{\mathbf{2}}$}$

Check:

$\begin{array}{rcl}16384 & = & 4(2)^{12}\\16384 & = & 4(4096)\\16384 & = & 16384\\\end{array}$

It checks.

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Answer:

...

Step-by-step explanation:

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