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Vinil7 [7]
3 years ago
9

1 7/9 as a mixed number

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
4 0

Answer:

1         8/9

Step-by-step explanation:

andrey2020 [161]3 years ago
4 0

Answer:

Step-by-step explanation: 17/9 = 1 and 8/9

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Joey fixes bicycles and charges a shop fee of $15 and $10 per hour for time worked. If t is the number of hours worked and C is
Bezzdna [24]
I beleive it is a because both variable could change
3 0
3 years ago
37. Verify Green's theorem in the plane for f (3x2- 8y2) dx + (4y - 6xy) dy, where C is the boundary of the
Nastasia [14]

I'll only look at (37) here, since

• (38) was addressed in 24438105

• (39) was addressed in 24434477

• (40) and (41) were both addressed in 24434541

In both parts, we're considering the line integral

\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy

and I assume <em>C</em> has a positive orientation in both cases

(a) It looks like the region has the curves <em>y</em> = <em>x</em> and <em>y</em> = <em>x</em> ² as its boundary***, so that the interior of <em>C</em> is the set <em>D</em> given by

D = \left\{(x,y) \mid 0\le x\le1 \text{ and }x^2\le y\le x\right\}

• Compute the line integral directly by splitting up <em>C</em> into two component curves,

<em>C₁ </em>: <em>x</em> = <em>t</em> and <em>y</em> = <em>t</em> ² with 0 ≤ <em>t</em> ≤ 1

<em>C₂</em> : <em>x</em> = 1 - <em>t</em> and <em>y</em> = 1 - <em>t</em> with 0 ≤ <em>t</em> ≤ 1

Then

\displaystyle \int_C = \int_{C_1} + \int_{C_2} \\\\ = \int_0^1 \left((3t^2-8t^4)+(4t^2-6t^3)(2t))\right)\,\mathrm dt \\+ \int_0^1 \left((-5(1-t)^2)(-1)+(4(1-t)-6(1-t)^2)(-1)\right)\,\mathrm dt \\\\ = \int_0^1 (7-18t+14t^2+8t^3-20t^4)\,\mathrm dt = \boxed{\frac23}

*** Obviously this interpretation is incorrect if the solution is supposed to be 3/2, so make the appropriate adjustment when you work this out for yourself.

• Compute the same integral using Green's theorem:

\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy = \iint_D \frac{\partial(4y-6xy)}{\partial x} - \frac{\partial(3x^2-8y^2)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = \int_0^1\int_{x^2}^x 10y\,\mathrm dy\,\mathrm dx = \boxed{\frac23}

(b) <em>C</em> is the boundary of the region

D = \left\{(x,y) \mid 0\le x\le 1\text{ and }0\le y\le1-x\right\}

• Compute the line integral directly, splitting up <em>C</em> into 3 components,

<em>C₁</em> : <em>x</em> = <em>t</em> and <em>y</em> = 0 with 0 ≤ <em>t</em> ≤ 1

<em>C₂</em> : <em>x</em> = 1 - <em>t</em> and <em>y</em> = <em>t</em> with 0 ≤ <em>t</em> ≤ 1

<em>C₃</em> : <em>x</em> = 0 and <em>y</em> = 1 - <em>t</em> with 0 ≤ <em>t</em> ≤ 1

Then

\displaystyle \int_C = \int_{C_1} + \int_{C_2} + \int_{C_3} \\\\ = \int_0^1 3t^2\,\mathrm dt + \int_0^1 (11t^2+4t-3)\,\mathrm dt + \int_0^1(4t-4)\,\mathrm dt \\\\ = \int_0^1 (14t^2+8t-7)\,\mathrm dt = \boxed{\frac53}

• Using Green's theorem:

\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dx = \int_0^1\int_0^{1-x}10y\,\mathrm dy\,\mathrm dx = \boxed{\frac53}

4 0
3 years ago
6 is added to the product of 7 and a number
notka56 [123]

The value of the expression will be equal to 55.

<h3>What is an expression?</h3>

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that 6 is added to the product of 7 and a number 7. The expression will be written as,

E = 7 x 7 + 6

E = 49 + 6

E = 55

Therefore, the value of the expression will be equal to 55.

To know more about an expression follow

brainly.com/question/11847301

#SPJ2

5 0
1 year ago
Read 2 more answers
Giving 1000 po iints<br><br> look at my proff ile
mixas84 [53]

Answer:

what about your pofile???

6 0
2 years ago
Read 2 more answers
A product is made up of three parts that act independently of each other. If any of the parts is defective, the product is defec
natali 33 [55]

Answer:

The probability that a product is defective is 0.2733.

Step-by-step explanation:

A product consists of 3 parts. If any one of the part is defective the whole product is considered as defective.

The probability of the 3 parts being defective are:

P (Part 1 is defective) = 0.05

P (part 2 is defective) = 0.10 P (part 3 is defective) = 0.15

Compute the probability that a product is defective as follows:

P (Defective product) = 1 - P (non-defective product)

= 1 - P (None of the 3 parts are defective)

= 1 - P (Part 1 not defective) × P (Part 2 not defective) × P (Part 1 not defective)

=1-[(1-0.05)\times(1-0.10)\times (1-0.15)]\\=1-[0.95\times0.90\times0.85]\\=1-0.72675\\=0.27325\\\approx0.2733

Thus, the probability that a product is defective is 0.2733.

3 0
3 years ago
Read 2 more answers
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