So if each equation for x x / a

Rewrite in simplest rational exponent form x^1/2*X^1/4

jasenka [17]

Answer:

$\sqrt[4]{x^3}$

Step-by-step explanation:

First, let's examine our original statement.

$x^{\frac{1}{2} }\cdot x^{\frac{1}{4}}$

Using exponent rules, we know that if we have $x^a \cdot x^b$ , then simplified, the answer will be equivalent to $x^{a+b}$ .

So we can simplify this by adding the exponents $\frac{1}{2}$ and $\frac{1}{4}$ .

Converting $\frac{1}{2}$ into fourths gets us $\frac{2}{4}$ .

$\frac{2}{4} + \frac{1}{4} = \frac{3}{4}$ .

So we now have $x^{\frac{3}{4}}$ .

When we have a number to a fraction power, it's the same thing as taking the denominator root of the base to the numerator power.

Basically, this becomes

$\sqrt[4]{x^3}$ . (The numerator is what we raise x to the power of, the denominator is the root we take of that).

Hope this helped!

4 0

3 years ago

Read 2 more answers

If x = 10, which lines are parallel? Check all that apply.

natita [175]

Answer:

b||c; c||d; b||d

Step-by-step explanation:

Substituting 10 for x, in the angle beside b we have

7(10)-5 = 70-5 = 65

In the angle beside c we have

10(10)+15 = 100+15 = 115

In the angle beside d we have

12(10)-5 = 120-5 = 115

In the angle beside we have

8(10)-25 = 80-25 = 55

The angle beside c has a vertical angle on the other side of c. This angle would be same-side interior angles with the angle beside b; this is because they are inside the block of lines made by b and c and on the same side of a, the transversal. These two angles are supplementary; this is because 65+115 = 180. Since these angles are supplementary, this means that b||c.

The angle beside c and the angle beside d would be alternate interior angles; this is because they are inside the block of lines made by c and d and on opposite sides of the transversal. These two angles are congruent; this means that c||d.

Since b||c and c||d, by the transitive property, b||d.

4 0

3 years ago

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What is 15-4x=-10-11x

RideAnS [48]

15-4X=-10-11X
-4X+11X=-10-15
7X=-25
X=-25/7
that's what it is

4 0

3 years ago

nickel has an approximate diameter of 20 mm and an approximate thickness of 2 mm what is the approximate volume of a stack of 40

ziro4ka [17]

Answer:

The approximate volume of a stack of 40 nickels is 25132.741 cubic milimeters.

Step-by-step explanation:

A nickel can be modelled by the formula of a right cylinder, the approximate volume of the stack of nickels ( $V_{net}$ ), measured in cubic milimeters, is the product of the number of elements ( $n$ ), no unit, and the volume of each element ( $V$ ), measured in cubic milimeters. That is: