The answer is 54494687431
All scalar multiples of the vector [ 4, 5] makes the
line y = 5/4 x.
The matrix A of the orthogonal projection onto the line L is made of the
coordinates of the projections of the base trajectories i and j onto the line L
printed in columns.
The line L: y = 5/4*x
Orthogonal line passing over the point (1, 0): y = -4/5 *x + 4/5
Point of Intersection: (16/41, 21/41)
Projections: P(i) = 16/41 i + 21/41 j, P(j) = 16/41 i + 21/41 j
The matrix:
A = || 16/41..16/41||
......|| 16/41....16/41 ||
Answer:
Third term is 67.
Step-by-step explanation:
Let the first term of the sequence be .
Given:
The second term is 5 more than the first term.
Second term =
Third term = First term + Second term =
Fourth term = Second term + Third term =
Sum of first 4 terms is 237. Therefore,
Now, the third term of the sequence is given as:
<span>36x³a + 45xa² =</span>9xa(4x²+5a)
Answer:
a. 8
b. 80
Step-by-step explanation: