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OleMash [197]
3 years ago
8

How many ways are there to split 10 people into five pairs? Pls give me answer fast!

Mathematics
1 answer:
alexandr402 [8]3 years ago
5 0

Answer:

945 arrangements

Step-by-step explanation:

(fifth term in the sequence with m=5 and five pairs for 10 people in total).

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Answer each of the questions for the following diagram:
sweet [91]

Answer:

1.  Complimentary angles

2.  3x+20 = 10x-15: x = 5

3.  I'm not sure on part 3, sorry.



5 0
3 years ago
Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
3 years ago
Marta made a fruit salad with 30 strawberries and 50 grapes. Assuming each strawberry contains 6 calories and each grape contain
olchik [2.2K]
Okay so i am no math genius but i did it like this, 30 strawberries and 50 grapes would be 80 fruits. say all 5 people got an equal amount so 80/5=16. so 16 pieces would be 8 each so 8 strawberries(sb) and 8 grapes(g). sb= 6 calories and g=3 calories. 48 calories for sb and 24 for g. 72 calories each. unless i did this totally wrong
4 0
3 years ago
Read 2 more answers
A carousel horse travels on a circular path with a radius of 15 ft. How many feet does the horse travel over an angle of 2π3 rad
snow_lady [41]

Answer:

arc\,\,length=10\,\pi\,ft\\arc\,\,length=31.41\,ft

Step-by-step explanation:

Recall that the formula for the length of an arc of circumference is given by the formula:

arc\,\,length=\theta\,R

where \theta is the radian form of central angle subtended , and R is the radius of the circumference. What is important is to have the angle given in radians for this formula to be valid.

In our case, the angle ( \frac{2\pi}{3} ) is already in radians, so we can apply the formula directly:

arc\,\,length=\theta\,R\\arc\,\,length=\frac{2\,\pi}{3} \,(15\,ft)\\arc\,\,length=10\,\pi\,ft\\arc\,\,length=31.41\,ft

6 0
3 years ago
A game designer must decide how to color five buildings that are in a row. Using only the colors yellow, green, red, and blue, e
earnstyle [38]

Answer:

The total of ways the buildings can be painted are  = 4 \times 3  \times 2  \times 2  \times 1 = 48 ways.

Step-by-step explanation:

i) color five buildings that are in a row.

ii) any two neighboring buildings must be different colors

iii) the first third and fifth buildings must be different colors.

iv) the number of ways to paint the fist building are 4.

v) the number of ways to paint the second building are 3.

vi) the number of ways to paint the third building are 2.

vii) the number of ways to paint the fourth building are 2.

viii) the number of ways to paint the last building are 1.

ix) therefore the total of ways the buildings can be painted are

   = 4 \times 3  \times 2  \times 2  \times 1 = 48 ways.

4 0
3 years ago
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