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mars1129 [50]
3 years ago
11

Which equation is equivalent to (2x^2+4x-7)(x-3)

Mathematics
1 answer:
Rasek [7]3 years ago
5 0

Answer:

2 x^3 - 2 x^2 - 19 x + 21

Step-by-step explanation:

Expand the following:

(2 x^2 + 4 x - 7) (x - 3)

Hint: | Multiply out (x - 3) (2 x^2 + 4 x - 7).

| | 2 x^2 | + | 4 x | - | 7

| | | | x | - | 3

| | -6 x^2 | - | 12 x | + | 21

2 x^3 | + | 4 x^2 | - | 7 x | + | 0

2 x^3 | - | 2 x^2 | - | 19 x | + | 21:

Answer: 2 x^3 - 2 x^2 - 19 x + 21

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The lengths of a lawn mower part are approximately normally distributed with a given mean = 4 in. and standard deviation = 0.2 i
Charra [1.4K]

Answer:

68 %

Step-by-step explanation:

Let's call X to the random variable ''lengths of a lawn mower part''.

X ~ N(given mean;standard deviation)

X ~ N(4 in;0.2 in)

To find the percentage,first we are going to turn this random variable X into a random variable Z. Z will be a N(0;1)

We do this by subtracting the given mean to the original variable and dividing by it deviation.

P (3.8 in < X < 4.2 in) =

P [(3.8 in - 4 in) / (0.2 in)] < [(X - 4 in)] / (0.2 in) < [(4.2 in - 4 in) / (0.2 in)]

P ( -1 < Z < 1 ) = P (Z < 1) - P (Z< -1)

Where we can find  P (Z < 1) and  P (Z< -1) in any table of a N(0;1)

P (Z < 1) - P (Z< -1) = 0.8413 - 0.1587 = 0.6826 = 68%

5 0
3 years ago
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The image of the point (2, 1) under a translation is (-3, -2). Find
nirvana33 [79]

Answer:

(-7, -12)

Explanation:

The translation of (2, 1) to (-3, -2) is 5 units left and 3 and 3 units down

2 - 5 = -3, x-coordinate = -3

1 - 3 = -2, y-coordinate = -2

Thus that makes the coordinates (-3, -2)

So that is taking away 5 from the x-axis and 3 away from the y-axis

-2 - 5 = -7, x-coordinate = -7

-9 - 3 = -12, y-coordinate = -12

Thus, the answer is (-7, -12)

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3 years ago
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A model predicts the profit, p of a company as p(x) = x3 – 3x2 – 16x + 48, where p is in thousands of dollars and x is number of
zavuch27 [327]
The first step is to determine the zeros of p(x).
From the Remainder Theorem, 
p(a) = 0  => (x-a) is a factor of p(x), and x=a is a zero of p(x).

Try x=3:
p(3) = 3^3 - 3*3^2 - 16*3 + 48 = 27 - 27 - 48 + 48 = 0
Therefore x=3 is a zero, and (x-3) is a factor of p(x).

Perform long division.
                    x²             -  16
      -------------------------------------
x-3 |  x³  -  3x²  -  16x  +  48
         x³  -  3x²
        -----------------------------------
                         -  16x  + 48
                         -  16x  +  48         

Note that x² - 6 = (x+4)(x-4).

Therefore the complete factorization of p(x) is
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To determine when p(x) is negative, we shall test between the zeros of p(x)
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----  ---------    ---------
  -4          0    
   0        48         +
   3           0
3.5   -1.875         -
   4           0

p(x) is negative in the interval x = (3, 4).

Answer
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